包含回显PHP变量的PHP include语句

Question

我从这里得到了所需的ID变量(可能有1-6个值)：

$new_product['ID'] =$row[2];

我需要的是根据这个变量回显一个单独的'php-include‘，比如：

<?php include 'includes/size/prod/echo $row[2].php'; ?>

其中包括/size/prod/1.php、includes/size/prod/2.php等

我不知道如何表达php中的“回声”。

Answer 1

有几种方法：

//Concatenate array value in double quotes:
<?php include "includes/size/prod/{$row[2]}.php"; ?>

//Concatenate array value outside of quotes:
<?php include "includes/size/prod/".$row[2].".php"; ?>
//or, using single quotes:
<?php include 'includes/size/prod/'.$row[2].'.php'; ?>

//Concatenate variable (not array value) in double quotes:
<?php $page = $row[2]; include "includes/size/prod/$page.php"; ?>

请参见：

• http://php.net/manual/en/language.operators.string.php
• PHP - concatenate or directly insert variables in string
• PHP include with a variable in the path

Answer 2

用这种技术包含你的PHP文件是非常危险的!！

您必须通过至少控制PHP包含的文件来防止这种情况发生

现在回答你的问题：

<?php 
// ? $row2 contains more than 1 php file to include ?
//   they are seperated by comma ?

$phpToInclude = NULL;
define(TEMPLATE_INCLUDE, 'includes/size/prod/');

if (isset($row[2])) {
    $phpToInclude = explode($row[2], ',');
}

if (!is_null($phpToInclude)) {
    foreach($phpToInclude as $f) {
        $include = sprintf(TEMPLATE_INCLUDE . '%s', $f);
        if (is_file($include)) {
            // add validator here !!
            include ($include);
        }
        else {
            // file not exist, log your error
        }
    }
}

?>

Answer 3

敬请使用以下工作代码

$row[2]         =   '';
$file_name      =   !empty($row[2])?$row[2]:'default';
$include_file   =  "includes/size/prod/".$file_name.".php";
include($include_file);