Switch语句+用户输入

Question

谢谢你抽出时间来帮助我。我需要这个switch语句来只接受整数1-4。任何其他输入的内容都将再次要求输入。输入5将退出系统。

     System.out.println("A random numbers list has been generated for you:\n ");

     System.out.println("Choose an option:\n1)Form list to be heapified.\n2)Enqueue the integer 10" +
        "\n3)Dequeue the integer 10.\n4)Print the updated heap.\n5)Quit the system \n>>"); 
     Scanner scanner = new Scanner( System.in );
     int var = 0;
     String input = scanner.next();
     int answer = Integer.parseInt(input);

     do{
        input = scanner.next();
        answer = Integer.parseInt(input);
        var = answer;

     switch(var){
        case 1:
           for (int i = 0; i < 20; i++) {
              h.insert(new Integer((int)(100 * Math.random())), i);
           }
           break;
        case 2:
           System.out.println("\nEnqueue-ing 10...\n");
                pushFoward(10, 20);//priority 20
           break;
        case 3:
        System.out.println("\nDequeue-ing 10...\n");
            dequeue;//priority highest deleted

           break;
        case 4:
           while (h.heapsize() > 0) {
              System.out.print(h.pop() + " ");
           } 
           break;
     } 
     }while(var ==1 || var==2 || var==3
     || var==4);

我似乎不能把它弄对。继续让事情变得更糟。

编辑：

 do{
    String input = scanner.next();
             int answer = Integer.parseInt(input);
     switch(var){
        case 1:
           for (int i = 0; i < 20; i++) {
              h.insert(new Integer((int)(100 * Math.random())), i);
           }
           break;
        case 2:
           System.out.println("\nEnqueue-ing 10...\n");
                h.pushFoward(10, 20);//priority 20
           break;
        case 3:
        System.out.println("\nDequeue-ing 10...\n");
            h.dequeue();//priority highest deleted

           break;
        case 4:
           while (h.heapsize() > 0) {
              System.out.print(h.pop() + " ");
           } 
           break;
           default: input = scanner.next();
            break;
     } 
     }while(var!=5)

；

Answer 1

您可以设置“默认”大小写。

default: doSomething();
                 break;

当用户输入一个不属于您的情况的值时，将调用此方法。

} while (answer != 5);

当输入5时，这应该会使循环中断。

编辑：

此外，您还需要打开answer变量而不是'var‘

switch(answer) {

Answer 2

尝试添加"default:“语句，如下所示：

    switch(var){
    case 1:
       for (int i = 0; i < 20; i++) {
          h.insert(new Integer((int)(100 * Math.random())), i);
       }
       break;
    case 2:
       System.out.println("\nEnqueue-ing 10...\n");
            pushFoward(10, 20);//priority 20
       break;
    case 3:
    System.out.println("\nDequeue-ing 10...\n");
        dequeue;//priority highest deleted

       break;
    case 4:
       while (h.heapsize() > 0) {
          System.out.print(h.pop() + " ");
       } 
       break;
    default:
        *Add whatever code you want to execute if its greater then or equal to 5 here!*

 }while(var ==1 || var==2 || var==3
 || var==4);

Answer 3

你不需要把它放在一个循环中。用例很简单：

• For 1-4 :做点什么，然后返回
• For 5: quit/return Everything
• else：

公共静态空main(String[]参数){

扫描仪扫描仪=新扫描仪(System.in)；int应答= Integer.parseInt(scanner.next())；开关(应答){案例1: System.out.println(1)；中断；案例2: System.out.println(2)；中断；案例3: System.out.println(3)；中断；案例4: System.out.println(4)；中断；案例5:返回；// System.exit(0)或按您的意愿退出: answer = Integer.parseInt(scanner.next())；}

}