我使用的是xUnit,如果T是自定义类型,它无法确定2个IEnumerable<T>是否相等。
我尝试过使用LINQ SequenceEqual,但由于T的实例不同,因此返回false;
下面是一个不起作用的IEqualityComparer的基本测试
[Fact]
public void FactMethodName()
{
var one = new[] { new KeywordSchedule() { Id = 1 } };
var two = new[] { new KeywordSchedule() { Id = 1 } };
Assert.Equal(one, two, new KeywordScheduleComparer());
}
public class KeywordScheduleComparer : IEqualityComparer<IEnumerable<KeywordSchedule>>
{
public bool Equals(IEnumerable<KeywordSchedule> x, IEnumerable<KeywordSchedule> y)
{
return Object.ReferenceEquals(x, y) || (x != null && y != null && x.SequenceEqual(y));
}
public int GetHashCode(IEnumerable<KeywordSchedule> obj)
{
if (obj == null)
return 0;
return unchecked(obj.Select(e => e.GetHashCode()).Aggregate(0, (a, b) => a + b)); // BAD
}
}我在集成测试中使用它,所以我在开始时将数据从IEnumerable插入到DB中,然后调用SUT从DB中检索数据并进行比较。
如果你能帮我做一个集合比较,我将不胜感激!
发布于 2013-09-11 00:16:14
我刚刚验证了这在xUnit.net 1.9.2中工作得很好:
public class MyClass
{
public int ID { get; set; }
public string Name { get; set; }
}
public class MyClassComparer : IEqualityComparer<MyClass>
{
public bool Equals(MyClass x, MyClass y)
{
return x.ID == y.ID;
}
public int GetHashCode(MyClass obj)
{
return obj.ID.GetHashCode();
}
}
public class ExampleTest
{
[Fact]
public void TestForEquality()
{
var obj1 = new MyClass { ID = 42, Name = "Brad" };
var obj2 = new MyClass { ID = 42, Name = "Joe" };
Assert.Equal(new[] { obj1 }, new[] { obj2 }, new MyClassComparer());
}
}所以我不是100%清楚为什么你需要额外的比较器。只需要一个比较器就足够了。
发布于 2013-09-10 22:04:30
嗯,你的实现还在等待中。您为IEnumerable<KeywordSchedule>实现了自定义比较器,但忘记了为KeywordSchedule实现相同的比较器。
x.SequenceEqual仍然使用Comparer<T>.Default,所以它用于引用比较,因此结果是假的。
public class KScheduleComparer : IEqualityComparer<KeywordSchedule>
{
public bool Equals(KeywordSchedule x, KeywordSchedule y)
{
return x.Id == y.Id;
}
public int GetHashCode(KeywordSchedule obj)
{
return obj.GetHashCode();
}
}然后修改KeywordScheduleComparer类中的Equals方法,如下所示
public class KeywordScheduleComparer : IEqualityComparer<IEnumerable<KeywordSchedule>>
{
public bool Equals(IEnumerable<KeywordSchedule> x, IEnumerable<KeywordSchedule> y)
{
return Object.ReferenceEquals(x, y) || (x != null && y != null && x.SequenceEqual(y, new KScheduleComparer()));
}
public int GetHashCode(IEnumerable<KeywordSchedule> obj)
{
if (obj == null)
return 0;
return unchecked(obj.Select(e => e.GetHashCode()).Aggregate(0, (a, b) => a + b)); // BAD
}
}发布于 2013-09-11 23:09:11
您可以使用FluentAssertions库更优雅地完成这项工作。它有很多用于集合的断言方法。
public class MyClass
{
public int ID { get; set; }
public string Name { get; set; }
protected bool Equals(MyClass other)
{
return ID == other.ID;
}
public override bool Equals(object obj)
{
if (ReferenceEquals(null, obj)) return false;
if (ReferenceEquals(this, obj)) return true;
if (obj.GetType() != GetType()) return false;
return Equals((MyClass) obj);
}
public override int GetHashCode()
{
unchecked
{
return (ID*397) ^ (Name != null ? Name.GetHashCode() : 0);
}
}
}
public class ExampleTest
{
[Fact]
public void TestForEquality()
{
var obj1 = new MyClass { ID = 42, Name = "Rock" };
var obj2 = new MyClass { ID = 42, Name = "Paper" };
var obj3 = new MyClass { ID = 42, Name = "Scissors" };
var obj4 = new MyClass { ID = 42, Name = "Lizard" };
var list1 = new List<MyClass> {obj1, obj2};
list1.Should().BeEquivalentTo(obj3, obj4);
}
}https://stackoverflow.com/questions/18720582
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