意外的PHP-CURL输出

Question

我试图弄清楚为什么下面的代码仍然在命令行上输出，即使最后没有echo、print_r或var_dump命令。我希望在变量中获得输出以便进一步处理，但是$result变量只有boolean数据类型。

$data_string = '{"query":"{  ethereum(network: bsc) {    arguments(      smartContractAddress: {is: \"0xBCfCcbde45cE874adCB698cC183deBcF17952812\"}      smartContractEvent: {is: \"PairCreated\"}      argument: {not: \"pair\"}      options: {desc: \"block.height\", limit: 10}    ) {      block {        height        timestamp {          unixtime        }      }      argument {        name        type      }      reference {        address        smartContract {          currency {            name          }        }      }    }  }}","variables":"{}"}';
$headers = array('Content-Type: application/json', 'X-API-KEY: BQYI5KOkokFE3CBqPfQvldOhXwVKWEf8' );
$ch = curl_init();
curl_setopt( $ch, CURLOPT_URL, 'https://graphql.bitquery.io/' );
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt( $ch, CURLOPT_HTTPHEADER, $headers);

$result = curl_exec($ch);
curl_close($ch);
//Output displayed at the command line without me specifically print/echo it ???

有没有人能帮我把输出正确地输出到变量$result？现在，我想要的输出直接显示在命令行上

Answer 1

CURLOPT_RETURNTRANSFER，false

尝试添加此参数