我希望使用GBM包进行逻辑回归,但它给出的答案略高于0-1范围。我已经尝试了0-1预测的建议分布参数(bernoulli和adaboost),但这实际上比使用gaussian更糟糕。
GBM_NTREES = 150
GBM_SHRINKAGE = 0.1
GBM_DEPTH = 4
GBM_MINOBS = 50
> GBM_model <- gbm.fit(
+ x = trainDescr
+ ,y = trainClass
+ ,distribution = "gaussian"
+ ,n.trees = GBM_NTREES
+ ,shrinkage = GBM_SHRINKAGE
+ ,interaction.depth = GBM_DEPTH
+ ,n.minobsinnode = GBM_MINOBS
+ ,verbose = TRUE)
Iter TrainDeviance ValidDeviance StepSize Improve
1 0.0603 nan 0.1000 0.0019
2 0.0588 nan 0.1000 0.0016
3 0.0575 nan 0.1000 0.0013
4 0.0563 nan 0.1000 0.0011
5 0.0553 nan 0.1000 0.0010
6 0.0546 nan 0.1000 0.0008
7 0.0539 nan 0.1000 0.0007
8 0.0533 nan 0.1000 0.0006
9 0.0528 nan 0.1000 0.0005
10 0.0524 nan 0.1000 0.0004
100 0.0484 nan 0.1000 0.0000
150 0.0481 nan 0.1000 -0.0000
> prediction <- predict.gbm(object = GBM_model
+ ,newdata = testDescr
+ ,GBM_NTREES)
> hist(prediction)
> range(prediction)
[1] -0.02945224 1.00706700伯努利:
GBM_model <- gbm.fit(
x = trainDescr
,y = trainClass
,distribution = "bernoulli"
,n.trees = GBM_NTREES
,shrinkage = GBM_SHRINKAGE
,interaction.depth = GBM_DEPTH
,n.minobsinnode = GBM_MINOBS
,verbose = TRUE)
prediction <- predict.gbm(object = GBM_model
+ ,newdata = testDescr
+ ,GBM_NTREES)
> hist(prediction)
> range(prediction)
[1] -4.699324 3.043440和adaboost:
GBM_model <- gbm.fit(
x = trainDescr
,y = trainClass
,distribution = "adaboost"
,n.trees = GBM_NTREES
,shrinkage = GBM_SHRINKAGE
,interaction.depth = GBM_DEPTH
,n.minobsinnode = GBM_MINOBS
,verbose = TRUE)
> prediction <- predict.gbm(object = GBM_model
+ ,newdata = testDescr
+ ,GBM_NTREES)
> hist(prediction)
> range(prediction)
[1] -3.0374228 0.9323279如果我做错了什么,我是需要对数据进行缩放( preProcess )(缩放、居中),还是需要手动设置值的上限/上限,如下所示:
prediction <- ifelse(prediction < 0, 0, prediction)
prediction <- ifelse(prediction > 1, 1, prediction)发布于 2011-12-07 15:50:40
来自?predict.gbm
返回一个预测向量。默认情况下,预测在f(x)的范围内。例如,对于伯努利损失,返回值是对数赔率等级,泊松损失是对数等级,coxph是对数危险等级。
如果type=为“response”,那么gbm将转换回与结果相同的级别。目前,这将产生的唯一影响是返回bernoulli的概率和poisson的预期计数。对于其他发行版,"response“和"link”返回相同的值。
因此,如果使用distribution="bernoulli",则需要将预测值转换为0,1:p <- plogis(predict.gbm(model))。使用distribution="gaussian"实际上是为了回归而不是分类,尽管我很惊讶预测不是0,1:我的理解是gbm仍然是基于树的,所以预测值应该不能超出训练数据中存在的值。
https://stackoverflow.com/questions/8410846
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