我一直在为一个脚本而苦苦挣扎,这个脚本将Pi的BCM引脚17,27和10打开1秒,然后关闭1秒,顺序大约100次。当我运行脚本时,LED1会打开,然后它会关闭,程序会关闭,并显示以下错误:
Traceback (most recent call last):
File "LedBlink.py", line 47, in <module>
LED2Blink()
File "LedBlink.py", line 27, in LED2Blink
GPIO.setup(LED2, GPIO.OUT)
RuntimeError: Please set pin numbering mode using GPIO.setmode(GPIO.BOARD) or GPIO.setmode(GPIO.BCM)
import RPi.GPIO as GPIO
import time
LED1 = 17
LED2 = 27
LED3 = 10
GPIO.setmode(GPIO.BCM)
def LED1Blink():
GPIO.setup(LED1, GPIO.OUT)
GPIO.output(LED1,True)
time.sleep(1)
GPIO.output(LED1,False)
time.sleep(1)
GPIO.cleanup()
def LED2Blink():
GPIO.setup(LED2, GPIO.OUT)
GPIO.output(LED2,True)
time.sleep(1)
GPIO.output(LED2,False)
time.sleep(1)
GPIO.cleanup()
def LED3Blink():
GPIO.setup(LED3, GPIO.OUT)
GPIO.output(LED3,True)
time.sleep(1)
GPIO.output(LED3,False)
time.sleep(1)
GPIO.cleanup()
i = 0
while i < 100:
LED1Blink()
LED2Blink()
LED3Blink()
i + 1
else:
print "finished loop"发布于 2015-04-07 09:50:07
问题是您在每个方法的末尾调用GPIO.cleanup()。如documentation中所述,您想要的是GPIO.cleanup(channel),其中Note that GPIO.cleanup() also clears the pin numbering system in use.对应于脚本中的LED1, LED2, LED3。
最佳做法是仅设置一次和cleanup ,例如
import RPi.GPIO as GPIO
import time
LED1 = 17
LED2 = 27
LED3 = 10
GPIO.setmode(GPIO.BCM)
GPIO.setup(LED1, GPIO.OUT)
GPIO.setup(LED2, GPIO.OUT)
GPIO.setup(LED3, GPIO.OUT)
def LED1Blink():
GPIO.output(LED1,True)
time.sleep(1)
GPIO.output(LED1,False)
time.sleep(1)
def LED2Blink():
GPIO.output(LED2,True)
time.sleep(1)
GPIO.output(LED2,False)
time.sleep(1)
def LED3Blink():
GPIO.output(LED3,True)
time.sleep(1)
GPIO.output(LED3,False)
time.sleep(1)
i = 0
if i < 100:
LED1Blink()
LED2Blink()
LED3Blink()
i + 1
else:
GPIO.cleanup()
print "finished loop"发布于 2018-03-11 17:21:12
永远不要多次调用GPIO.cleanup(),因为在清除引脚的同时,它也会清除引脚模式!所以,如果你在程序之间调用了它,那么下一条语句的执行就不会有引脚模式,这会给出一个错误。TraceBack(最近呼叫时间)和GPIO.setmode(GPIO.BOARD)或GPIO.setmode(GPIO.BCM)错误
因此,如果满足某些条件,请始终在程序可能结束/中断的地方使用它。
https://stackoverflow.com/questions/29478216
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