我的一个表中有两个列,分别称为TIME_OUT和TIME_IN。这两个都是十进制值。我基本上想总结一下这些列的差异。我有下面的查询,它输出的差值没有问题,但我想对差值求和:
SELECT (TIME_IN-TIME_OUT) AS DIFF FROM TABLE_timelogs WHERE YEAR(LOG_DATE) = YEAR(NOW());
+------+
| DIFF |
+------+
| 10.0 |
| 4.0 |
| 3.0 |
+------+有没有一种方法可以将SUM集成到查询中,以便最终输出为17.0?提前谢谢你!
发布于 2014-04-02 04:37:46
将SUM添加到您的查询中,以便查询为:
SELECT SUM(TIME_IN-TIME_OUT) AS DIFF
FROM TABLE_timelogs
WHERE YEAR(LOG_DATE) = YEAR(NOW());这将添加“diff”列的内容。
https://stackoverflow.com/questions/22796310
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