我的应用程序下载并解压缩特定文件夹中的文件:
output = new FileOutputStream(realpath, true);
output.write(buffer, 0, bytesRead);
ZipFile zipFile = new ZipFile(realpath);有了新引入的ACTION_OPEN_DOCUMENT_TREE意图,我想让用户选择该文件夹。
在测试我的onActivityResult中接收到的值时,我得到了一个类似/tree/primary:mynewfolder的路径,而不是像/sdcard/mynewfolder这样的物理真实路径。
Uri treeUri = data.getData();
String sPath = treeUri.getPath();
Log.v("Path from Tree ", sPath);我的解压缩方法需要真实的路径:
ZipFile zipFile = new ZipFile(realpath);我如何从棒棒糖(API21& 22)中提供的URI中获得像/sdcard/mynewfolder这样的真实路径?
发布于 2015-04-22 14:32:35
从URI获取实际路径的过程与之前相同,但增加了一点:
Uri uri = data.getData();
Uri docUri = DocumentsContract.buildDocumentUriUsingTree(uri,
DocumentsContract.getTreeDocumentId(uri));
String path = getPath(this, docUri);带有中间方法的getPath()方法的要点可以在这里找到:getPath()
发布于 2021-01-28 17:29:30
不需要检查android版本..
public static string GetRealPath(DocumentFile treeUri)
{
if (treeUri == null)
return "";
var path1 = treeUri.Uri.Path;
if (path1.StartsWith("/tree/"))
{
var path2 = path1.Remove(0, "/tree/".Length);
if (path2.StartsWith("primary:"))
{
var primary = path2.Remove(0, "primary:".Length);
if (primary.Contains(':'))
{
var storeName = "/storage/emulated/0/";
var last = path2.Split(':').LastOrDefault();
var realPath = storeName + last;
return realPath;
}
}
else
{
if (path2.Contains(':'))
{
var path3 = path2.Split(':').FirstOrDefault();
var storeName = path3;
var last = path2.Split(':').LastOrDefault();
var realPath = "/" + storeName + "/" + last;
return realPath;
}
}
}
return path1;
}https://stackoverflow.com/questions/29713587
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