用于球员运动控制的C#单位双跳编码

Question

using UnityEngine;
using System.Collections;

public class PlayerMovement : MonoBehaviour 
{
public float speed          = 3.0f;
public float jumpSpeed          = 200.0f;
public bool grounded            = true;
public float time           = 4.0f;     



// Use this for initialization
void Start () 
{

}

// Update is called once per frame
void FixedUpdate () 
{
    Vector3 x = Input.GetAxis("Horizontal")* transform.right * Time.deltaTime *      speed;

    if (time <= 2)
    {
    if(Input.GetButtonDown("Jump"))
        {
                Jump();
        }

    }

    transform.Translate(x);

    //Restrict Rotation upon jumping of player object
    transform.rotation = Quaternion.LookRotation(Vector3.forward);


}
void Jump()
    {
        if (grounded == true)
        {
            rigidbody.AddForce(Vector3.up* jumpSpeed);


            grounded = false;
        }

    }
void OnCollisionEnter (Collision hit)
{
    grounded = true;
    // check message upon collition for functionality working of code.
    Debug.Log ("I am colliding with something");
}

}

应该在哪里，什么类型的编码可以让它在回到地面之前跳两次？

有一个物体上面有精灵纸，我已经获得了基于物理引擎的约束运动和正常跳跃的统一。但我希望运动更有活力，只在没有接地的情况下跳两次，并在一定的时间范围内跳跃两次，就像在地面休息时在几毫秒间隔内按下跳跃按钮来重置位置一样。

Answer 1

这应该能起到作用：

private bool dblJump = true;

void Jump()
{
    if (grounded == true)
    {
        rigidbody.AddForce(Vector3.up* jumpSpeed);

        grounded = false;
    } 
    else if (!grounded && dblJump)
    {
        rigidbody.AddForce(Vector3.up* jumpSpeed);

        dblJump = false;
    }

}

void OnCollisionEnter (Collision hit)
{
    grounded = true;
    dblJump = true;
    // check message upon collition for functionality working of code.
    Debug.Log ("I am colliding with something");
}