ORA-00936:缺少表达式oracle

Question

我有这个问题

SELECT DAL_ROWNOTABLE.DAL_ID FROM 
(
    SELECT ticket.id AS "DAL_ID",  ROWNUMBER ( Order By ticket.id  )  AS "DAL_ROWNUMBER" 
    FROM ticket_table ticket 
    WHERE ( ticket.type = N'I' ) 
    AND 
    ( 
        ticket.tenant IS NULL OR ticket.tenant IN 
        (
            SELECT  * FROM 
            ( 
                SELECT tenant_group_member.tenant_id 
                FROM tenant_group_member 
                WHERE tenant_group_member.tenant_group = HEXTORAW('30B0716FEB5F4E4BB82A7B7AA3A1A42C') 
                ORDER BY ticket.id 
            ) 
         ) 
     )
) DAL_ROWNOTABLE 
WHERE DAL_ROWNOTABLE.DAL_ROWNUMBER BETWEEN 1 AND 21

抛出ORA-00936缺失表达式的allow查询有什么问题？有没有人？任何帮助都将在first order by的开头的appreciated...Error :80处抛出：

Answer 1

您的查询可以大大简化。它有额外的子查询层和in子查询中不必要的order by。只需使用rownum即可实现rownumber的功能

SELECT DAL_ROWNOTABLE.DAL_ID
FROM (SELECT ticket.id AS "DAL_ID" 
      FROM ticket_table ticket 
      WHERE (ticket.type = N'I' ) AND 
            (ticket.tenant IS NULL OR
             ticket.tenant IN (SELECT tgm.tenant_id 
                               FROM tenant_group_member tgm
                               WHERE tgm.tenant_group = HEXTORAW('30B0716FEB5F4E4BB82A7B7AA3A1A42C') 
                              ) 
            )
      ORDER BY ticket.id
     ) DAL_ROWNOTABLE 
WHERE rownum <= 21;

Answer 2

ORA-00936通常表示存在语法错误。

ROWNUMBER不是一个Oracle函数。除非您有一个同名的用户定义函数，否则我怀疑您要查找的函数是ROW_NUMBER()。