我使用的是SQL Server2008,我正在尝试用FOR XML的EXPLICIT模式生成一个自定义的xml。
我有一个一对多的关系,查询如下
select
p.personid, p.firstname, a.P_City
from
tblPeople p with (nolock)
left outer join
tblAddresses a with (nolock) on p.personid = a.personid
where
p.personid = 120773

我想要父母的人和孩子的地址可能是多个,因为人们的地址有一对多的关系。
我编写了以下查询
select 1 as TAG,
null as parent,
p.personid as [person!1!personid],
p.FirstName as [person!1!firstname],
null as [addr!2!]
from tblPeople p with (nolock) where p.PersonID in (120773,117396)
union all
select 2,1,
p.PersonID, p.FirstName, a.P_City from tblAddresses a with(nolock), tblPeople p
where p.PersonID=a.PersonID and p.PersonID in (120773,117396)
for xml explicit输出如下所示,它是与person嵌套的破碎的xml肯定是我的代码出了问题。
<person personid="117396" firstname="David"/>
<person personid="120773" firstname="Doyle">
<addr>Mount Rainier</addr>
<addr>Annapolis</addr>
</person>有人能帮帮我吗!
发布于 2012-10-05 04:53:34
我建议你抛弃FOR XML EXPLICIT,转而使用FOR XML PATH/ROOT。
在此处使用此查询:
select
p.personid AS "@ID",
p.firstname, p.LastName,
(
SELECT AddressID AS "@ID", City
FROM dbo.Address a
WHERE a.PersonID = p.PersonID
FOR XML PATH('addr'), TYPE
) AS Addresses
from
Person p with (nolock)
where
p.personid = 120773
FOR XML PATH('Person'), ROOT('People')您将获得以下输出XML:
<People>
<Person ID="120773">
<firstname>John</firstname>
<LastName>Doyle</LastName>
<Addresses>
<addr ID="1">
<City>Annapolis</City>
</addr>
<addr ID="2">
<City>Mount Rainier</City>
</addr>
</Addresses>
</Person>
</People>根据需要对其进行调整。阅读有关FOR XML PATH on MSDN的更多详细信息。
发布于 2012-10-11 00:46:14
为了正确使用For XML EXPLICIT,ORDER BY是基础。看看这个
select 1 as TAG,
null as parent,
p.personid as [person!1!personid],
p.FirstName as [person!1!firstname],
null as [addr!2!]
from tblPeople p with (nolock) where p.PersonID in (120773,117396)
union all
select 2,1,
p.PersonID, p.FirstName, a.P_City from tblAddresses a with(nolock), tblPeople p
where p.PersonID=a.PersonID and p.PersonID in (120773,117396)
ORDER BY [person!1!personid], [addr!2!]
for xml explicithttps://stackoverflow.com/questions/12735615
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