URL中包含空格的file_get_contents

Question

我有一个问题，即使我将空格替换为%20并获得此内容，浏览器获得的最终url也会将"%20“转换为"%2520”。

这是我的代码，有什么建议可以让它工作吗？这看起来很简单，但我被卡住了:/

<?php
//$_GET['song'] will contain a song name with spaces
$song = str_replace(array("%20", "&", "?" , "/"), array(" ", "", "", ""), $_GET['song']);

// I use this to check how the GET 'song' looks after the str_replace
$list = "http://www.lyrdb.com/lookup.php?q=" . $song . "&for=fullt";
echo "list url is " . $list . "<hr>";

$content = file_get_contents("http://www.lyrdb.com/lookup.php?q=" . str_replace(" ", "%20", $song) . "&for=fullt");

echo $content;
?>

如果你去http://webservices.lyrdb.com/lookup.php?q=red%20hot%20chili%20peppers&for=fullt，结果应该会输出一个歌词代码列表。

当我访问我的网站/?song=red辣辣椒时，它也会将空格转换为%20，但如果浏览器似乎将%转换为%25。

有人能帮帮我吗？

Answer 1

$song = $_GET['song']);

$url = "http://www.lyrdb.com/lookup.php?for=fullt&q=";

echo "list url is " . htmlentities($url . $song) . "<hr>";

$content = file_get_contents($url . urlencode($song));

echo $content;

Answer 2

$data = json_encode($_POST);

$url = "http://www.index.com?data=";

echo file_get_contents($url . urlencode($data));