我已经简单地上传了:
$path = "uploads/";
$actual_image_name = time().$session_id.".".$ext;
$tmp = $_FILES['photoimg']['tmp_name'];
move_uploaded_file($tmp, $path.$actual_image_name);如何为这个函数添加imagejpeg?我希望总是保存JPG格式的图像。
发布于 2013-01-28 02:22:16
试试这个:
<?php
$path = "uploads/";
$img = $_FILES['photoimg']['tmp_name'];
$dst = $path . $_FILES['photoimg']['name'];
if (($img_info = getimagesize($img)) === FALSE)
die("Image not found or not an image");
$width = $img_info[0];
$height = $img_info[1];
switch ($img_info[2]) {
case IMAGETYPE_GIF : $src = imagecreatefromgif($img); break;
case IMAGETYPE_JPEG : $src = imagecreatefromjpeg($img); break;
case IMAGETYPE_PNG : $src = imagecreatefrompng($img); break;
default : die("Unknown filetype");
}
$tmp = imagecreatetruecolor($width, $height);
imagecopyresampled($tmp, $src, 0, 0, 0, 0, $width, $height, $width, $height);
imagejpeg($tmp, $dst.".jpg");
?>发布于 2013-01-28 02:02:42
确保安装了GD库,并使用它将gif或png转换为jpg,如
if ($_FILES["photoimg"]["type"] == "image/jpeg" || $_FILES["photoimg"]["type"] == "image/png" || $_FILES["photoimg"]["type"] == "image/gif" )
{
if ($_FILES["photoimg"]["type"] == "image/png" || $_FILES["photoimg"]["type"] == "image/gif" )
{
imagejpeg(imagecreatefromstring(file_get_contents($_FILES["photoimg"]["tmp_name"])), "converted.jpg");
$actual_image_name = time().$session_id.".".$ext;
move_uploaded_file("converted.jpg", $path.$actual_image_name);
}
else
{
$actual_image_name = time().$session_id.".".$ext;
$tmp = $_FILES['photoimg']['tmp_name'];
move_uploaded_file($tmp, $path.$actual_image_name);
}
}https://stackoverflow.com/questions/14550299
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