Django表单总是显示错误“此字段是必需的”

Question

当我呈现我的表单时，django总是在每个字段上显示错误消息"This field is required“，即使表单没有提交。可能的问题是什么？

这是我的模型表格

class MMEditidStateForm(forms.ModelForm):
  class Meta:
     model = models.MMEditidState
     exclude = ('status_id',)

这是我的模型

class MMEditidState(models.Model):
  state_id = models.IntegerField(primary_key = True)
  state_dremelid = models.ForeignKey(MMDremelDump, db_column = 'state_dremelid')
  assignee = models.CharField(max_length = 50)
  state = models.CharField(max_length = 50)
  role = models.CharField(max_length = 50)
  date = models.DateTimeField() 
  class Meta:
     db_table = u'mm_editid_state'
  def __unicode__(self):
     return u'%s %s' % (self.state_dremelid, self.assignee)

这是我的观点

def qcthisedit(request, get_id):
  dremel_id = MMEditidState.objects.filter(pk=get_id).values('state_dremelid')
  if request.method == "POST":
     form = forms.MMEditidStateForm(request.POST)
     if form.is_valid():
        form.save()
      return http.HttpResponseRedirect('/mmqc/dremel_list/')
  else:
     form = forms.MMEditidStateForm(request.POST)
  return shortcuts.render_to_response('qcthisedit.html',locals(),
                                  context_instance = context.RequestContext(request))

现在我只是在模板中将我的表单呈现为

    <table>
    <h3>Submit this form if there are no errors</h3>

    <form action="." method="post">
    {{form.as_table}}      
    </table>
    <input type="submit" value="Submit">
    <INPUT TYPE="BUTTON" VALUE="Go Back" ONCLICK="history.go(-1)"></form><br> 

请让我知道问题出在哪里？以前我没有收到这个错误信息

Answer 1

因为您总是使用request.POST实例化您的表单，即使您实际上并不是在向它发帖。在else子句中，删除request.POST。

Answer 2

或使用

form = forms.MMEditidStateForm(request.POST or None)

不带if条件，如下所示：

def qcthisedit(request, get_id):
  dremel_id = MMEditidState.objects.filter(pk=get_id).values('state_dremelid')
  form = forms.MMEditidStateForm(request.POST or None)
  if form.is_valid():
     form.save()
     return http.HttpResponseRedirect('/mmqc/dremel_list/')

  return shortcuts.render_to_response('qcthisedit.html',locals(),
                                  context_instance = context.RequestContext(request))

Answer 3

对于那些仍在寻找答案的人:我也有同样的问题。在这种情况下，我的建议是更新这一行：

form = forms.MMEditidStateForm(request.POST or None)

希望能有所帮助。