Java spring bean配置错误

Question

在我使用GWT开发的web应用程序Hibernate ans Spring中，我在jobClass -context.xml文件中设置应用程序bean时遇到了这种情况。

我在运行时得到以下错误：

Error 500 Error creating bean with name 'schedulerFactory' defined in class path resource [application-context.xml]:
Cannot resolve reference to bean 'cronTrigger' while setting bean property 'triggers' with key [0];

nested exception is org.springframework.beans.factory.BeanCreationException:
Error creating bean with name 'cronTrigger' defined in class path resource [application-context.xml]:
Cannot resolve reference to bean 'exampleJob1' while setting bean property 'jobDetail';

nested exception is org.springframework.beans.factory.BeanCreationException:
Error creating bean with name 'exampleJob1' defined in class path resource [application-context.xml]:
Initialization of bean failed;

nested exception is org.springframework.beans.TypeMismatchException:
Failed to convert property value of type [fr.web.utils.ExampleJob] to required type [java.lang.Class] for property 'jobClass';

nested exception is java.lang.IllegalArgumentException:
Cannot convert value of type [fr.web.utils.ExampleJob] to required type [java.lang.Class] for property 'jobClass':
PropertyEditor [org.springframework.beans.propertyeditors.ClassEditor] returned inappropriate value

下面是我的Java类：

public class ExampleJob extends QuartzJobBean {
    private AbsenceDao absenceDao; 
    @Override
    protected void executeInternal(JobExecutionContext context)
    throws JobExecutionException {
        List untreatedDemands = new ArrayList();
        untreatedDemands = absenceDao.getDemandsAskedNotValidated();
    }
    public AbsenceDao getAbsenceDao() {
        return absenceDao;
    }
    public void setAbsenceDao(AbsenceDao absenceDao) {
        this.absenceDao = absenceDao;
    }
}

下面是我的应用程序-context.xml：

    <!-- variables d'environnement - fichier properties -->
    <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer" id="placeholderconfig">
        <property name="fileEncoding" value="UTF-8"/>
        <property name="locations">
            <list>
                <value>classpath:internal.properties</value>
            </list>
        </property>
    </bean>

    <!-- Configuration du crontrigger -->
    <bean id="schedulerFactory" class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
        <property name="triggers">
            <list>
                <ref bean="cronTrigger" />
            </list>
        </property>
    </bean>
    <bean id="cronTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
        <property name="jobDetail">
            <ref local="exampleJob1" />
        </property>

        <property name="cronExpression">
            <util:constant static-field="fr.web.utils.APP_VAR.CRON_EXPRESSION" />
        </property>
    </bean>

    <bean id="jobClass" class="fr.web.utils.ExampleJob">
        <property name="absenceDao" ref="absenceDao"/>
    </bean>

    <bean id="exampleJob1" class="org.springframework.scheduling.quartz.JobDetailBean">
        <property name="jobClass" ref="jobClass" />
        <property name="jobDataAsMap">
            <map>
                <entry key="timeout" value="5" />
            </map>
        </property>
    </bean>

    <tx:annotation-driven transaction-manager="hibernateTransactionManager"/>

    <!-- Bean containing all the properties of the application -->
    <bean class="fr.web.utils.ApplicationProperties" id="applicationProperties" lazy-init="true" scope="singleton">
        <constructor-arg index="0" value="classpath:internal.properties"/>
    </bean>

    <!-- Bean DAO -->
    <bean abstract="true" id="abstractDao">
        <property name="sessionFactory" ref="sessionFactory"/>
    </bean>
    <bean class="fr.web.dao.AbsenceDao" id="absenceDao" parent="abstractDao"/>

    </bean>
</beans>

Answer 1

属性jobClass需要class，而您已经给出了bean的reference，因此请更改

<bean id="exampleJob1" class="org.springframework.scheduling.quartz.JobDetailBean">
    <property name="jobClass" ref="jobClass" />
    <property name="jobDataAsMap">
        <map>
            <entry key="timeout" value="5" />
        </map>
    </property>
</bean>

to (备注：下面的value属性)

<bean id="exampleJob1" class="org.springframework.scheduling.quartz.JobDetailBean">
    <property name="jobClass" value="fr.acensi.web.utils.ExampleJob" />
    <property name="jobDataAsMap">
        <map>
            <entry key="timeout" value="5" />
        </map>
    </property>
</bean>

Answer 2

这里有另一个选项，你可能认为更整洁或不整洁，我喜欢它，因为它保持了上下文的清晰度。

<bean id="exampleJob1" class="org.springframework.scheduling.quartz.JobDetailBean">
  <property name="jobClass">
    <bean factory-bean="jobClass" factory-method="getClass" />
  </property>
</bean>

正如Jigar Joshi所描述的那样，问题的解决方案略有不同。它允许您将bean jobClass实例化与JobDetailbean的构建分离开来。