我基本上是在找人在这件事上给我指出正确的方向。我通读了一些Microsoft文档,但这并不是很有帮助。这是我第一次尝试使用XML。
我正在编写一个应用程序,它需要存储已知用户的列表和每个用户创建的别名列表。我已经知道了如何在应用程序关闭时将我的列表序列化并存储到XML文件中,并在应用程序再次打开时让它检索这些列表,但我不想将用户和别名的列表保存在内存中。
为了让它工作,我需要能够在运行时搜索、编辑和附加到XML文件。
我设想的XML结构类似于:
<UserRecord>
<User>Username-1</User>
<AliasRecord>
<Alias>Alias-1</Alias>
<Number>6135551234</Number>
</AliasRecord>
<AliasRecord>
<Alias>Alias-2</Alias>
<Number>6131238888</Number>
</AliasRecord>
</UserRecord>每个用户只有一个用户名,但可以有多个别名。我需要有能力添加用户,添加别名到新的或现有的用户,并更改现有的别名。用户名永远不会改变,但可以删除整个用户记录。
到目前为止,我用C#完成的惟一一个XML使用序列化,但我不认为这种方法适用于上面的情况。
private void WriteXML()
{
try
{
System.Xml.Serialization.XmlSerializer XMLwriter = new System.Xml.Serialization.XmlSerializer(typeof(MessageRecord));
System.IO.StreamWriter XMLfile = new System.IO.StreamWriter("Saved MessageRecords.xml");
foreach (MessageRecord mr in OutgoingMessages)
{
XMLwriter.Serialize(XMLfile, mr);
}
XMLfile.Close();
}
catch (Exception e)
{
MessageBox.Show(e.Message);
}
}发布于 2014-08-19 01:42:39
创建两个类来表示UserRecord和AliasRecord。
public class UserRecord
{
public string User { get; set; }
public List<AliasRecord> AliasRecords { get; set; }
}
public class AliasRecord
{
public string Alias { get; set; }
public string Number { get; set; }
}像这样填充它们:
var userRecord = new UserRecord
{
User = "UserName1",
AliasRecord = new List<AliasRecord> {
new AliasRecord { Alias = "Alias1", Number = "12345678" },
new AliasRecord { Alias = "Alias2", Number = "23456789" }
}
};并使用以下代码对其进行序列化/反序列化:
public static class XmlHelper
{
public static bool NewLineOnAttributes { get; set; }
/// <summary>
/// Serializes an object to an XML string, using the specified namespaces.
/// </summary>
public static string ToXml(object obj, XmlSerializerNamespaces ns)
{
Type T = obj.GetType();
var xs = new XmlSerializer(T);
var ws = new XmlWriterSettings { Indent = true, NewLineOnAttributes = NewLineOnAttributes, OmitXmlDeclaration = true };
var sb = new StringBuilder();
using (XmlWriter writer = XmlWriter.Create(sb, ws))
{
xs.Serialize(writer, obj, ns);
}
return sb.ToString();
}
/// <summary>
/// Serializes an object to an XML string.
/// </summary>
public static string ToXml(object obj)
{
var ns = new XmlSerializerNamespaces();
ns.Add("", "");
return ToXml(obj, ns);
}
/// <summary>
/// Deserializes an object from an XML string.
/// </summary>
public static T FromXml<T>(string xml)
{
XmlSerializer xs = new XmlSerializer(typeof(T));
using (StringReader sr = new StringReader(xml))
{
return (T)xs.Deserialize(sr);
}
}
/// <summary>
/// Deserializes an object from an XML string, using the specified type name.
/// </summary>
public static object FromXml(string xml, string typeName)
{
Type T = Type.GetType(typeName);
XmlSerializer xs = new XmlSerializer(T);
using (StringReader sr = new StringReader(xml))
{
return xs.Deserialize(sr);
}
}
/// <summary>
/// Serializes an object to an XML file.
/// </summary>
public static void ToXmlFile(Object obj, string filePath)
{
var xs = new XmlSerializer(obj.GetType());
var ns = new XmlSerializerNamespaces();
var ws = new XmlWriterSettings { Indent = true, NewLineOnAttributes = NewLineOnAttributes, OmitXmlDeclaration = true };
ns.Add("", "");
using (XmlWriter writer = XmlWriter.Create(filePath, ws))
{
xs.Serialize(writer, obj);
}
}
/// <summary>
/// Deserializes an object from an XML file.
/// </summary>
public static T FromXmlFile<T>(string filePath)
{
StreamReader sr = new StreamReader(filePath);
try
{
var result = FromXml<T>(sr.ReadToEnd());
return result;
}
catch (Exception e)
{
throw new Exception("There was an error attempting to read the file " + filePath + "\n\n" + e.InnerException.Message);
}
finally
{
sr.Close();
}
}
}示例用法:
var result = XmlHelper.ToXml(userRecord);结果:
<UserRecord>
<User>Username1</User>
<AliasRecords>
<AliasRecord>
<Alias>Alias1</Alias>
<Number>12345678</Number>
</AliasRecord>
<AliasRecord>
<Alias>Alias2</Alias>
<Number>23456789</Number>
</AliasRecord>
</AliasRecords>
</UserRecord>https://stackoverflow.com/questions/25368083
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