有没有一种简单的方法将
java.lang.Iterable[_]到一个
Scala.Iterable[_]发布于 2009-07-02 07:21:52
是使用隐式转换:
import java.lang.{Iterable => JavaItb}
import java.util.{Iterator => JavaItr}
implicit def jitb2sitb[T](jit: JavaItb[T]): Iterable[T] = new SJIterable(jit);
implicit def jitr2sitr[A](jit: JavaItr[A]): Iterator[A] = new SJIterator(jit)这样就可以很容易地实现:
class SJIterable[T](private val jitb: JavaItr[T]) extends Iterable[T] {
def elements(): Iterator[T] = jitb.iterator()
}
class SJIterator[T](private val jit: JavaItr[T]) extends Iterator[T] {
def hasNext: Boolean = jit hasNext
def next: T = jit next
}发布于 2019-06-30 18:38:01
启动Scala 2.13时,package scala.jdk.CollectionConverters将替换过时的packages scala.collection.JavaConverters/JavaConversions
import scala.jdk.CollectionConverters._
// val javaIterable: java.lang.Iterable[Int] = Iterable(1, 2, 3).asJava
javaIterable.asScala
// Iterable[Int] = List(1, 2, 3)https://stackoverflow.com/questions/1072784
复制相似问题