这是我正在做的一个项目的一部分。我有两个桌面java应用程序,一个运行在服务器上(它有真正的IP),另一个是客户端。我只想从连接到服务器应用程序的摄像头流式传输实时视频,并在客户端应用程序上播放它。我想要从多个摄像头进行此流媒体。
我已经在Xuggler,Red5,VLCj之间寻找了几天的搜索。我只是不知道我应该从哪里开始,因为我是编程中与媒体打交道的新手。
有什么想法我应该从哪里开始呢?
提前感谢
发布于 2011-12-04 02:05:15
我建议你使用VLCJ,因为除了实时视频流之外,你的应用程序还可以使用VLC媒体播放器的所有功能。此外,它还可用于Linux、Windows和Mac。如果你可以用VLC直播你的摄像头,那么你也可以用VLCJ来做同样的事情。
具体使用方法请参考VLCJ wiki page。他们在wiki中提供了许多示例。以下是使用VLCJ的Http流的示例。从VLCJ示例中复制。
/*
* This file is part of VLCJ.
*
* VLCJ is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* VLCJ is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with VLCJ. If not, see <http://www.gnu.org/licenses/>.
*
* Copyright 2009, 2010, 2011 Caprica Software Limited.
*/
package uk.co.caprica.vlcj.test.streaming;
import uk.co.caprica.vlcj.player.MediaPlayerFactory;
import uk.co.caprica.vlcj.player.headless.HeadlessMediaPlayer;
import uk.co.caprica.vlcj.test.VlcjTest;
/**
* An example of how to stream a media file over HTTP.
* <p>
* The client specifies an MRL of <code>http://127.0.0.1:5555</code>
*/
public class StreamHttp extends VlcjTest {
public static void main(String[] args) throws Exception {
if(args.length != 1) {
System.out.println("Specify a single MRL to stream");
System.exit(1);
}
String media = args[0];
String options = formatHttpStream("127.0.0.1", 5555);
System.out.println("Streaming '" + media + "' to '" + options + "'");
MediaPlayerFactory mediaPlayerFactory = new MediaPlayerFactory(args);
HeadlessMediaPlayer mediaPlayer = mediaPlayerFactory.newHeadlessMediaPlayer();
mediaPlayer.playMedia(media, options);
// Don't exit
Thread.currentThread().join();
}
private static String formatHttpStream(String serverAddress, int serverPort) {
StringBuilder sb = new StringBuilder(60);
sb.append(":sout=#duplicate{dst=std{access=http,mux=ts,");
sb.append("dst=");
sb.append(serverAddress);
sb.append(':');
sb.append(serverPort);
sb.append("}}");
return sb.toString();
}
}https://stackoverflow.com/questions/8368300
复制相似问题