Angularjs过滤器嵌套对象

Question

我在angular中有这样的嵌套对象。有没有办法过滤嵌套属性？

<li ng-repeat="shop in shops | filter:search">
search.locations.city_id = 22

我只显示了父元素，但希望按这两个元素进行过滤，如下所示：

search = 
  category_id: 2
  locations:
    city_id: 368

[
 name: "xxx"
 category_id: 1
 locations: [
   city_id: 368
   region_id: 4
  ,
   city_id: 368
   region_id: 4
  ,
   city_id: 368
   region_id: 4
  ]
,
 name: "xxx"
 category_id: 2
 locations: [
   city_id: 30
   region_id: 4
  ,
   city_id: 22
   region_id: 2
  ]
]

Answer 1

是的，你可以，如果我正确理解你的例子的话。

根据您的集合的大小，计算您在ng-repeat中迭代的集合可能更好，这样过滤器就不会随着模型的变化而不断地计算。

http://jsfiddle.net/suCWn/

如果我没理解错的话，基本上你是这样做的：

$scope.search = function (shop) {

    if ($scope.selectedCityId === undefined || $scope.selectedCityId.length === 0) {
        return true;
    }

    var found = false;
    angular.forEach(shop.locations, function (location) {          
        if (location.city_id === parseInt($scope.selectedCityId)) {
            found = true;
        }
    });

    return found;
};

Answer 2

您也可以像这样过滤(版本1.2.13+)

<li ng-repeat="shop in shops | filter: { locations: [{ city_id: search.locations.city_id }] }">

Answer 3

更新了"Words Like Jared“答案，使用正则表达式检查它是否包含搜索词。这种方式会在你输入1个数字时开始过滤，这样你就不必匹配整个单词了

JSfiddle

    angular.forEach(shop.locations, function (location) {          
        if (checknum(location.city_id)) {
            found = true;
        }
    });

    function checknum(num){
        var regx = new RegExp($scope.selectedCityId);
        return regx.test(num);
    };