我想按列(所有者)对数据帧进行分组,并输出一个新的数据帧,该数据帧包含每个观察值中每种类型的因子的计数。实际数据帧相当大,有10个不同的因素。
下面是一些示例输入:
library(dplyr)
df = tbl_df(data.frame(owner=c(0,0,1,1), obs1=c("quiet", "loud", "quiet", "loud"), obs2=c("loud", "loud", "quiet", "quiet")))
owner obs1 obs2
1 0 quiet loud
2 0 loud loud
3 1 quiet quiet
4 1 loud quiet我正在寻找类似如下的输出:
out = data.frame(owner=c("0", "0", "1", "1"), observation=c("obs1", "obs2", "obs1", "obs2"), quiet=c(1, 0, 1, 2), loud=c(1, 2, 1, 0))
owner observation quiet loud
1 0 obs1 1 1
2 0 obs2 0 2
3 1 obs1 1 1
4 1 obs2 2 0融化让我走到了半路:
melted = tbl_df(melt(df, id=c("owner")))
owner variable value
1 0 obs1 quiet
2 0 obs1 loud
3 1 obs1 quiet
4 1 obs1 loud
5 0 obs2 loud
6 0 obs2 loud
7 1 obs2 quiet
8 1 obs2 quiet但是最后一步是什么呢?如果'value‘是一个数字,我会这样做:
melted %>% group_by(owner, variable) %>% summarise(counts=sum(value))非常感谢!
发布于 2017-01-19 15:05:15
2017年的答案是
library(dplyr)
library(tidyr)
gather(df, key, value, -owner) %>%
group_by(owner, key, value) %>%
tally %>%
spread(value, n, fill = 0)它给出了输出
Source: local data frame [4 x 4]
Groups: owner, key [4]
owner key loud quiet
* <dbl> <chr> <dbl> <dbl>
1 0 obs1 1 1
2 0 obs2 2 0
3 1 obs1 1 1
4 1 obs2 0 22019年的答案是:
gather(df, key, value, -owner) %>%
count(owner, key, value) %>%
spread(value, n, fill = 0)发布于 2014-09-12 23:45:16
您可以在dplyr中使用tidyr
library(dplyr)
library(tidyr)
df %>%
gather(observation, Val, obs1:obs2) %>%
group_by(owner,observation, Val) %>%
summarise(n= n()) %>%
ungroup() %>%
spread(Val, n, fill=0)它给出了输出
# owner observation loud quiet
#1 0 obs1 1 1
#2 0 obs2 2 0
#3 1 obs1 1 1
#4 1 obs2 0 2发布于 2015-12-12 09:08:21
如果你想放弃dplyr,你可以分成几个列表。
df <- split(df, list(df[[obs1]], df[[obs2]])如果需要count,只需创建一个sapply或lapply调用来遍历列表并获取每个列表的计数。或者你想要的任何其他函数。
https://stackoverflow.com/questions/25811756
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