C++：在数组中查找最大值的问题

Question

感谢你们每一位提前给予的帮助。

问题一：

我今天正在写一个程序，它应该显示用户将输入的10个值中的最高值。然而，每当我测试程序和输入值时，它似乎显示了不止一个“最大值”。我想这可能与我过度使用cout和cin函数有关。程序似乎会沿着用户输入的值列表向下移动，并选择列表中最高的值。

例如：

2, 4, 5, 1, 7, 8, 3, 2, 9

它将选择5、8和9作为最高值。

问题二：

我想知道是否有一种方法可以简化我在下面编写的代码(参考cout和cin函数)。例如，制作一个while函数，并具有如下函数：

 while (something)
      cout << "Please input the number of pancakes person " << x << "has ate.\n"
      cin >> something // Either x or a pancakes function. I tried both.
      count++ // Sorry, I would just assume that the count function would be used in this scenario.

问题3：

关于我的程序中的最大值输出，会不会是我把数组搞乱了？

代码：

#include <iostream>

using namespace std;

int main()
{
    int pancakes [10];
    int x;
    int largestValue = 0;

    cout << "Please input the number of pancakes person 1 has ate.\n";
    cin >> pancakes[0];
    cout << "Please input the number of pancakes person 2 has ate.\n";
    cin >> pancakes[1];
    cout << "Please input the number of pancakes person 3 has ate.\n";
    cin >> pancakes[2];
    cout << "Please input the number of pancakes person 4 has ate.\n";
    cin >> pancakes[3];
    cout << "Please input the number of pancakes person 5 has ate.\n";
    cin >> pancakes[4];
    cout << "Please input the number of pancakes person 6 has ate.\n";
    cin >> pancakes[5];
    cout << "Please input the number of pancakes person 7 has ate.\n";
    cin >> pancakes[6];
    cout << "Please input the number of pancakes person 8 has ate.\n";
    cin >> pancakes[7];
    cout << "Please input the number of pancakes person 9 has ate.\n";
    cin >> pancakes[8];
    cout << "Please input the number of pancakes person 10 has ate.\n";
    cin >> pancakes[9];

    for (int x = 0; x < 10; x++)
        if (pancakes[x] > largestValue)
    {
            largestValue = pancakes[x];
        cout << "The person who ate the most pancakes ate: " << largestValue << " pancakes.\n";
    }

    return 0;

}

Answer 1

问题是，每次在这段代码中选择一个新的max-value时都会打印出来：

for (int x = 0; x < 10; x++) {
    if (pancakes[x] > largestValue) {
        largestValue = pancakes[x];
    }
    cout << "The person who ate the most pancakes ate: " << largestValue << " pancakes.\n";
}

相反，它应该是：

for (int x = 0; x < 10; x++) {
    if (pancakes[x] > largestValue) {
        largestValue = pancakes[x];
    }
}
cout << "The person who ate the most pancakes ate: " << largestValue << " pancakes.\n";

顺便说一下:我想你要么用“吃”(不用“有”)，要么用“吃过了”。

关于没有硬编码人员数量的另一个问题:首先，我将使用std::vector而不是数组。然后你会问，有多少人。现在，您可以创建一个具有如此多次迭代的for-循环。在每次迭代中，用户都会被问到person X吃了多少煎饼，然后使用std::vector::push_back将这个数字附加到向量的末尾。最后，你，你只需要像你已经做的那样选择最大的数字。只要让for循环的上限为< vector.size()即可。

Answer 2

for (int x = 0; x < 10; x++)
    if (pancakes[x] > largestValue)
{
        largestValue = pancakes[x];
    cout << "The person who ate the most pancakes ate: " << largestValue << " pancakes.\n";
}

一旦找到比以前看到的更大的结果，您就会立即显示结果。您应该等到检查完所有的值。

for (int x = 0; x < 10; x++)
    if (pancakes[x] > largestValue)
    {
        largestValue = pancakes[x];
    }

cout << "The person who ate the most pancakes ate: " << largestValue << " pancakes.\n";

Answer 3

cout语句应该在循环之外。每次输入if语句时都会打印当前的cout (每次找到新的largestValue时)。

for (int x = 0; x < 10; x++) {
    if (pancakes[x] > largestValue)
    {
        largestValue = pancakes[x];
    }
}

cout << "The person who ate the most pancakes ate: " << largestValue << " pancakes.\n";