blocks|key|969232|text|我认为你可以用这里说的话走很长一段路：Calculate+relative+time+in+C#|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|969233|逻辑就在那里，如果一种不同语言的解决方案适合您，那么做与javascript等效的代码也不是太难。|969234|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/11/how-do-i-calculate-relative-time^0|J|T|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]]|C|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@]|C|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]]]

I think you can come a long way with what is said here: <a href="https://stackoverflow.com/questions/11/how-do-i-calculate-relative-time">Calculate relative time in C#</a> 
The logic is there, and it's not too hard to do the javascript equivalent if a solution in a different language suits you.

blocks|key|3051470|text|可能有更优雅的解决方案(寻找自然语言格式)，但我个人找不到任何解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3051471|我建议使用阈值来计算从now到您要格式化的日期的距离。|offset|length|style|CODE|3051472|伪解：|3051473|diff+=+now+-+date

if+(diff+<+one_day)+
++++format+for+today
if+(diff+<+two_days)+
++++format+for+tomorrow
if+(diff+<+one_week)
++++format+using+days+from+now
.
.
.|code-block|syntax|javascript|3051474|只要将compare与diff的abs值一起使用，这种比较将对过去和将来的日期都有效。通过检查diff是正数还是负数来显示先前的时间单位或现在开始的时间单位。|3051475|对于上午、下午、晚上等，您只需检查日期中的时间，对于您点击的格式类型，可以将时间显示为数字(较远)或自然语言(最近或较近的日期)。|3051476|entityMap^0|0|B|3|0|0|0|B|4|G|3|1B|4|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@$D|W|E|X|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|Y|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|Z|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|10|8|@$D|11|E|12|F|G]|$D|13|E|14|F|G]|$D|15|E|16|F|G]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|17|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|T|$]]

There might be more elegant solutions out there (look for Natural language formatting), but personally I couldn't find any. 

I would suggest calculating the distance from <code>now</code> to the date you're formatting, and using thresholds. 

Pseudo solution:

<pre><code>diff = now - date

if (diff &lt; one_day) 
 format for today
if (diff &lt; two_days) 
 format for tomorrow
if (diff &lt; one_week)
 format using days from now
.
.
.
</code></pre>

The comparison will work for both past and future dates, as long as you use compare with the <code>abs</code> value of <code>diff</code>. Display timeunit ago or timeunit from now by checking if <code>diff</code> is positive or negative.

For the morning, afternoon, evening etc. you only need to check for the time of day in the date, and regarding the formatting type you hit, either display the time as numbers (far away), or natural language (recent or near date).

blocks|key|3051505|text|从该链接->+How+do+I+calculate+relative+time+in+C#?|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3051506|function+posted(t)+{+
var+now+=+new+Date();+
var+diff+=+parseInt((now.getTime()+-+Date.parse(t))+/+1000);+
if+(diff+<+60)+{+return+'less+than+a+minute+ago';+}+
else+if+(diff+<+120)+{+return+'about+a+minute+ago';+}+
else+if+(diff+<+(2700))+{+return+(parseInt(diff+/+60)).toString()+%2B+'+minutes+ago';+}+
else+if+(diff+<+(5400))+{+return+'about+an+hour+ago';+}+
else+if+(diff+<+(86400))+{+return+'about+'+%2B+(parseInt(diff+/+3600)).toString()+%2B+'+hours+ago';+}+
else+if+(diff+<+(172800))+{+return+'1+day+ago';+}++
else+{return+(parseInt(diff+/+86400)).toString()+%2B+'+days+ago';+}+
}+|code-block|syntax|javascript|3051507|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/11/how-do-i-calculate-relative-time^0|7|13|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

From this link -&gt; <a href="https://stackoverflow.com/questions/11/how-do-i-calculate-relative-time">How do I calculate relative time in C#?</a>
<pre><code>function posted(t) { 
var now = new Date(); 
var diff = parseInt((now.getTime() - Date.parse(t)) / 1000); 
if (diff &lt; 60) { return 'less than a minute ago'; } 
else if (diff &lt; 120) { return 'about a minute ago'; } 
else if (diff &lt; (2700)) { return (parseInt(diff / 60)).toString() + ' minutes ago'; } 
else if (diff &lt; (5400)) { return 'about an hour ago'; } 
else if (diff &lt; (86400)) { return 'about ' + (parseInt(diff / 3600)).toString() + ' hours ago'; } 
else if (diff &lt; (172800)) { return '1 day ago'; } 
else {return (parseInt(diff / 86400)).toString() + ' days ago'; } 
} 
</code></pre>

blocks|key|735612|text|+++++++++++++++++++function+gett($sam){
+++++++++++++++++++$times+=+time()+-+$sam;
++++++++++++++++++++if+($times+==+60){
++++++++++++++++++++$times+=+"a+minute+ago";
++++++++++++++++++++}
++++++++if+(($times+!=+1)+&&+($times+<+60)+&&+($times+!=+0)){
++++++++$times+=+"$times+seconds+ago";
++++++++}
++++++++if+($times+==+0){
++++++++$times+=+"less+than+a+second+ago";
++++++++}
++++++++if+($times+==+1){
++++++++$times+=+"a+second+ago";
++++++++}

++++++++if+($times+>+60+&&+$times+<+3600){
++++++++$times+=+ceil($times/60)."+minutes+ago";
++++++++}

++++++++if($times+==+3600){
++++++++$times+=+"an+hour+ago";
++++++++}
++++++++if($times+>+3600+&&+$times+<+86400){
++++++++$times+=+ceil($times/3600)."+hours+ago";
++++++++}
++++++++if($times+==+86400){
++++++++$times+=+"a+day+ago";
++++++++}
++++++++if($times+>+86400){
++++++++$times+=+ceil($times/86400)."+days+ago";
++++++++}
++++++++return+$times;+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|735613|用法：$updated+=+gett(+$timestamp+)；其中$timestamp非常不言自明。|unstyled|735614|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code> function gett($sam){
 $times = time() - $sam;
 if ($times == 60){
 $times = "a minute ago";
 }
 if (($times != 1) &amp;&amp; ($times &lt; 60) &amp;&amp; ($times != 0)){
 $times = "$times seconds ago";
 }
 if ($times == 0){
 $times = "less than a second ago";
 }
 if ($times == 1){
 $times = "a second ago";
 }

 if ($times &gt; 60 &amp;&amp; $times &lt; 3600){
 $times = ceil($times/60)." minutes ago";
 }

 if($times == 3600){
 $times = "an hour ago";
 }
 if($times &gt; 3600 &amp;&amp; $times &lt; 86400){
 $times = ceil($times/3600)." hours ago";
 }
 if($times == 86400){
 $times = "a day ago";
 }
 if($times &gt; 86400){
 $times = ceil($times/86400)." days ago";
 }
 return $times; }
</code></pre>

Usage:
$updated = gett($timestamp);
where $timestamp is pretty self-explanatory..

Convert 2010-04-16 16:30:00 to "Tomorrow Afternoon" or convert another date to "this afternoon", "next year", "next week wednesday". You get the picture.
Anyone know of a PHP or Javascript library that can do this?

Convert 2010-04-16 16:30:00 to "Tomorrow Afternoon"

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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将2010-04-16 16:30:00转换为“明天下午”，或将另一个日期转换为“今天下午”、“明年”、“下周星期三”。你就明白了。有人知道有PHP或Javascript库可以做到这一点吗？

问将2010-04-16 16:30:00转换为“明天下午”
EN

回答 4

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问将2010-04-16 16:30:00转换为“明天下午”EN

回答 4

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问将2010-04-16 16:30:00转换为“明天下午”
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