由django序列化程序生成的json无法在angular ui网格中呈现

Question

angular ui-grid不能显示我的视图生成的json，如下所示：

class DummyResponse(APIView):



     def get(self, request, pk, format='None'):
         GuestEntryModel = get_model('buddy', 'GuestEntry')
         print "GuestEntryModel.objects.all",GuestEntryModel.objects.all()
         serialized_data = serializers.serialize("json", GuestEntryModel.objects.all(),fields=('model'))
         print "serialized_data::",serialized_data
         return Response(serialized_data)

从该视图生成的json如下所示：

"[{\"fields\": {}, \"model\": \"buddy.guestentry\", \"pk\": 1}, {\"fields\": {}, \"model\": \"buddy.guestentry
\", \"pk\": 2}, {\"fields\": {}, \"model\": \"buddy.guestentry\", \"pk\": 3}, {\"fields\": {}, \"model
\": \"buddy.guestentry\", \"pk\": 4}, {\"fields\": {}, \"model\": \"buddy.guestentry\", \"pk\": 5}, 
{\"fields\": {}, \"model\": \"buddy.guestentry\", \"pk\": 6}, {\"fields\": {}, \"model\": \"buddy.guestentry
\", \"pk\": 7}, {\"fields\": {}, \"model\": \"buddy.guestentry\", \"pk\": 8}]"

Answer 1

请展示您的角度代码，我认为当您获得数据时，您必须遍历数据并将其放入变量中，如下面的示例所示

$scope.posts = [];
$http.get('/api/posts').then(function (result) {
    angular.forEach result.data, function (item) {
        $scope.posts.push( item);
    }
}