巨蟒石布剪刀

Question

我在这部分作业上遇到了麻烦。我必须声明游戏的胜利者，然后输入到一个函数中。一旦我输入了所有的if语句，我就必须创建一个函数def playGame()。这必须包括：

showRules()
user = getUserChoice()
computer = getComputerChoice()
declareWinner(user, computer)

def playGame():
    showRules()
    user = getUserChoice()
    computer = getComputerChoice()
    declareWinner(user, computer)

print("**** Rock-Paper-Scissors ****")

#Display game rules
def showRules():
    print("Rules: Each player chooses either Rock, Paper, or Scissors.")
    print("\tThe winner is determined by the following rules:")
    print("\t\tScissors cuts Paper   --> Scissors wins")
    print("\t\tPaper covers Rock     --> Paper wins")
    print("\t\tRock smashes Scissors --> Rock Wins")


#User selection
def getUserChoice():
    choice = (input("Make your selection (Rock, Paper, or Scissors). ")).lower()
    return choice

#obtain computer input
def getComputerChoice():
    import random
    rnum = random.randint(1,3)
    if rnum == 1:
        print("The computer has chosen Rock.")
    if rnum == 2:
        print("The computer has chosen Paper.")
    if rnum == 3:
        print("The computer has chosen Scissors.")
    return rnum

#Declare winner
def declareWinner(user, rnum):
    print("\n\nuser: ", user)
    print("rnum: ", rnum)    

    if ((user == "rock") and (rnum == 3)):
        print("Rock smashes Scissors --> Player wins!")    

    if ((user == "paper") and (rnum == 1)):
        print("Paper covers Rock --> Player wins!")

    if ((user == "Scissors") and (rnum == 2)):
        print("Scissors cuts Paper --> Player wins!")

下面是我运行程序时得到的输出：

**** Rock-Paper-Scissors ****
playGame()
Rules: Each player chooses either Rock, Paper, or Scissors.
    The winner is determined by the following rules:
        Scissors cuts Paper   --> Scissors wins
        Paper covers Rock     --> Paper wins
        Rock smashes Scissors --> Rock Wins
Make your selection (Rock, Paper, or Scissors). ROCk
The computer has chosen Rock.


user:  rock
rnum:  1

我需要输出如下所示：

Rules: Each player chooses either Rock, Paper, or Scissors.
    The winner is determined by the following rules:
        Scissors cuts Paper   --> Scissors wins
        Paper covers Rock     --> Paper wins
        Rock smashes Scissors --> Rock Wins
Make your selection (Rock, Paper, or Scissors). Paper

The computer has chosen Paper.

Paper covers Rock --> Player wins!

请帮帮忙。

我相信有更有效的方法可以做到这一点。在本课程的这一点上，我们正在使用函数，我需要知道如何合并它们以使程序函数正常工作。

Answer 1

你只有3条if语句--你的程序只知道在这些情况下该怎么做：

if ((user == "rock") and (rnum == 3)):
if ((user == "paper") and (rnum == 1)):
if ((user == "Scissors") and (rnum == 2)):

你必须包括一些平局，获胜和失败的东西

if ((user == "rock") and (rnum == 1)):
    #Whatever you want it to do
if ((user == "rock") and (rnum == 2)):
    #Stuff
if ((user == "rock") and (rnum == 3)):
    #Etc

Answer 2

看看你的情况；没有一个与你提供的样本中发生的情况相匹配。您不具备user == rock和rnum == 1的条件。这就是为什么您的条件语句中没有任何print语句被打印出来的原因。

Answer 3

您的代码可能不完整，或者缺少您选择的大小写。您的代码中没有平局，但结果显示是平局。

另外，我会使用if和elif来模仿“大小写”，就像你在其他语言中做的那样，并规范化用户输入：

rock == 1
paper == 2

这样你就可以更容易地比较它们；

if user == rnum:
 # print tie message
else:
    if user == 1 and rnum ==2:
     #dosomething
     elif user == 1 and rnum == 3:
     # do something else

诸若此类

另一种选择是嵌套if语句

if user == rnum:
# print tie
 else:
    if user == 1:
       if rnum == 2:
        #print
        elif rnum == 2:
        #print
    if user == 2: