创建了下面的make time以显示两周一次的日期
<?php
$date1 = "07/05/2013";
$date2 = date('M j, Y', strtotime($date1 . " + 14 day"));
$date3 = date('M j, Y', strtotime($date2 . " + 14 day"));
$date4 = date('M j, Y', strtotime($date3 . " + 14 day"));
$date5 = date('M j, Y', strtotime($date4 . " + 14 day"));
$date6 = date('M j, Y', strtotime($date5 . " + 14 day"));
$date7 = date('M j, Y', strtotime($date6 . " + 14 day"));
$date8 = date('M j, Y', strtotime($date7 . " + 14 day"));
$date9 = date('M j, Y', strtotime($date8 . " + 14 day"));
$date10 = date('M j, Y', strtotime($date9 . " + 14 day"));
$date11 = date('M j, Y', strtotime($date10 . " + 14 day"));
$date12 = date('M j, Y', strtotime($date11 . " + 14 day"));
$date13 = date('M j, Y', strtotime($date12 . " + 14 day"));
$date14 = date('M j, Y', strtotime($date13 . " + 14 day"));
$date15 = date('M j, Y', strtotime($date14 . " + 14 day"));
$date16 = date('M j, Y', strtotime($date15 . " + 14 day"));
$date17 = date('M j, Y', strtotime($date16 . " + 14 day"));
$date18 = date('M j, Y', strtotime($date17 . " + 14 day"));
?>我怎么才能让它按月分组?假设我想知道有多少日期在8月或12月。另外,如果我想在年底前得到多少个日期呢?我们将非常感谢您的帮助。
发布于 2013-07-19 03:03:50
试试这个:
<?php
// initiate months
$month_arr = Array();
for ($i=1; $i<=12; $i++){
// no. of dates
$month_arr[$i] = 0;
}
$date_arr = Array();
$date_start = "07/05/2013";
$date_arr[] = date('M j, Y', strtotime($date_start));
for ($i=1; $i<=17; $i++){
$date_temp = date('M j, Y', strtotime($date_arr[$i-1] . " + 14 day"));
$month = date('n', strtotime($date_temp));
$month_arr[$month] += 1;
$date_arr[] = $date_temp;
}
foreach ($month_arr as $k => $v){
echo "<BR>Month: " . $k . ", No. of dates: " . $v;
}
// all dates
echo "<BR>All dates<BR>";
var_dump ($date_arr);
?>您可以扩展此逻辑以按月对实际日期进行分组,而不是仅获取一个月中的日期计数。这就是解决方案:
<?php
// initiate months
$month_arr = Array(
'January' => Array('num_dates'=>0, 'dates'=>Array()) ,
'February' => Array('num_dates'=>0, 'dates'=>Array()),
'March' => Array('num_dates'=>0, 'dates'=>Array()),
'April' => Array('num_dates'=>0, 'dates'=>Array()),
'May' => Array('num_dates'=>0, 'dates'=>Array()),
'June' => Array('num_dates'=>0, 'dates'=>Array()),
'July' => Array('num_dates'=>0, 'dates'=>Array()),
'August' => Array('num_dates'=>0, 'dates'=>Array()),
'September' => Array('num_dates'=>0, 'dates'=>Array()),
'October' => Array('num_dates'=>0, 'dates'=>Array()),
'November' => Array('num_dates'=>0, 'dates'=>Array()),
'December' => Array('num_dates'=>0, 'dates'=>Array())
);
$date_arr = Array();
$date_start = "07/05/2013";
$date_arr[] = date('M j, Y', strtotime($date_start));
for ($i=1; $i<=17; $i++){
$date_temp = date('M j, Y', strtotime($date_arr[$i-1] . " + 14 day"));
$month = date('F', strtotime($date_temp));
$month_arr[$month]['dates'][] = $date_temp;
$month_arr[$month]['num_dates'] += 1;
$date_arr[] = $date_temp;
}
foreach ($month_arr as $k => $v){
if (!empty($v)){
if ($v['num_dates'] != 0){
echo "<BR><BR>Month: " . $k;
echo "<BR>No. of dates: " . $v['num_dates'];
foreach ($v['dates'] as $k1=>$v1){
echo "<BR>" . $v1;
}
}
}
}
?>在这一点上,$month_arr应该具备了您需要的一切。
发布于 2013-07-19 04:05:13
我不太清楚您所说的按月分组是什么意思,但这将使用一个数组来声明所有日期,并且您可以更改$limit变量以增加或减少日期的数量。change $dates to and original date $left是数组中还剩多少天(它在命中第一天后触发,可以更改为在最后一天触发),$amount是8月份的日期数量
<?php
$limit = 17;
$dates = array("07-05-2013");
for ($i=1; $i<=$limit; $i++){
$dates[$i]=date('d-m-Y', strtotime($dates[$i-1] . "+ 14 days"));
}
foreach (array_keys($dates) as $key){
$value = date('m', strtotime($dates[$key]));
if ($value == "08"){
$amount = $amount + 1;
}
if ($amount == 1){
$left = $limit-$key;
}
}
print_r ($dates);
echo "<br>";
echo $amount . "<br>" . $left;
?>发布于 2013-07-19 02:51:25
只需添加一条if语句,并在整个12个月内递增...如果月份相同
$n=1;
$month=array();//dumpyour dates in an array
$date=array()
while($k<30){
if (date('n', strtotime($date[$k]))==date('n', strtotime($date[$k-1])){
echo $date[$k++];
$m = date('n', strtotime($date[$k]));
$month[$m]=++$n;
}
else{
.....
}
}https://stackoverflow.com/questions/17731572
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