如何在iOS中向UIPasteboard写入字符串值和从其中读取字符串值？

Question

我有以下测试，不及格

NSString * expectedValue = @"achilles";

UIPasteboard *pasteboard = [UIPasteboard pasteboardWithName:@"pb1" create:YES];
pasteboard.persistent = YES;

pasteboard.string = expectedValue;    
STAssertEqualObjects(expectedValue, [pasteboard string], @"get written value from pasteboard");

[pasteboard setString:expectedValue];
STAssertEqualObjects(expectedValue, [pasteboard string], @"get written value from pasteboard");

两个断言都失败，

'achilles' should be equal to '(null)'

我是错误地向粘贴板写入，还是从粘贴板读取，还是两者都有？

Answer 1

我假设问题如下：

UIPasteboard的string属性定义为(see the docs)

@property(nonatomic, copy) NSString *string;  

这意味着如果你给它分配一个字符串，它将被复制，即一个新的对象被创建。当您重新读取它并将其与原始对象进行比较时，比较肯定会失败。

Answer 2

如果您正在从UIPasteBoard中写入或读取字符串，则可以通过访问

   [UIPasteboard generalPasteboard].string = @"your string";

   NSString *str =  [UIPasteboard generalPasteboard].string];

Answer 3

对于读写NSString，你可以使用通用的粘贴板。

有两种简单的方法来...

//Method 1
NSString * str=@"your String";
UIPasteboard * pasteboard=[UIPasteboard generalPasteboard];
[pasteboard setString:];

//Method 2
NSData *data = [str dataUsingEncoding:NSUTF8StringEncoding];
[pasteboard setData:data forPasteboardType:(NSString *)kUTTypeText];

你可以像下面这样读 NSString

   UIPasteboard * pasteboard=[UIPasteboard generalPasteboard];

    //Method 1
    NSLog(@"Text =%@",[pasteboard string]);

    //Method 2
    NSData * data = [pasteboard dataForPasteboardType:(NSString*)kUTTypeText];
    NSString * str =[[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
    NSLog(@"str =%@",str);

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