从C到HLA的转换

Question

我在将这段C代码转换成HLA时遇到了一些问题，我想知道是否有人能帮我。我的代码的目的是反复提示用户输入十进制值。最后，程序应该读出输入的所有数字的总和。

bool keepGoing;
int goal = O, total = 0, j = 0;
keepGoing = true;

printf("Feed Me: ");
scanf("%d", &goal);

total = goal;

while (keepGoing) {
    scanf("%d", &j);

    if (j >= goal)
        keepGoing = false;

    total += j;
    goal = j;
}

printf("Your total is %d\n", total);

Answer 1

您的位置如下：

program DoIt;
#include( "stdlib.hhf" );

static
    keepGoing : boolean;
    goal : int32 := 0;
    total : int32 := 0;
    j : int32 := 0;

begin DoIt;

    mov (true,keepGoing);
    stdout.put ("Feed Me: ");

    // scanf ( "%d", &goal );
    stdin.geti32();
    mov (eax, goal);

    mov (eax, total);

    while (keepGoing) do

        // scanf( "%d", &j );
        stdin.geti32();
        mov (eax, j);

        if (eax >= goal) then
            mov (false, keepGoing);
        endif;

        add (eax,total);
        mov (eax,goal);

    endwhile;

    stdout.put ("Your total is ", total, nl);

end DoIt;

现在尝试使用仅的寄存器，而不是存储(static下的变量)。

我建议使用the "HLA Language Reference Manual" and the "HLA Standard Library Manual"。