随机数和多个按钮c#

Question

我对如何让这个程序做一些特定的事情感到困惑，还有一个问题供我自己将来参考：

问:你能用按钮做if语句吗例如: if (点击button1)这样做，否则if (button2被点击)这样做

我的程序的目标是帮助学习基本的整数数学，四个部分是加法，减法，乘法和模数。我有3个文本框，第一个是显示的问题，第二个是用户的答案，第三个是答案是否正确

我目前设置的内容：

        private void button1_Click(object sender, EventArgs e)
    {
        Random random1 = new Random();
        int randomNumber1 = random1.Next(6, 11);
        Random random2 = new Random();
        int randomNumber2 = random2.Next(1, 6);
        textBox1.Text = "What is " + randomNumber1 + " + " + randomNumber2 + " ?";
    }

    private void button2_Click(object sender, EventArgs e)
    {
        Random random1 = new Random();
        int randomNumber1 = random1.Next(6, 11);
        Random random2 = new Random();
        int randomNumber2 = random2.Next(1, 6);
        textBox1.Text = "What is " + randomNumber1 + " - " + randomNumber2 + " ?";
    }

    private void button3_Click(object sender, EventArgs e)
    {
        Random random1 = new Random();
        int randomNumber1 = random1.Next(6, 11);
        Random random2 = new Random();
        int randomNumber2 = random2.Next(1, 6);
        textBox1.Text = "What is " + randomNumber1 + " * " + randomNumber2 + " ?";
    }

    private void button4_Click(object sender, EventArgs e)
    {
        Random random1 = new Random();
        int randomNumber1 = random1.Next(6, 11);
        Random random2 = new Random();
        int randomNumber2 = random2.Next(1, 6);
        textBox1.Text = "What is " + randomNumber1 + " % " + randomNumber2 + " ?";
    }

    private void button5_Click(object sender, EventArgs e)
    {
        Random random1 = new Random();
        int randomNumber1 = random1.Next(6, 11);
        Random random2 = new Random();
        int randomNumber2 = random2.Next(1, 6);




        if (Convert.ToInt16(textBox2.Text) == (randomNumber1) + (randomNumber2))
            textBox3.Text = "Correct!";
        else if (Convert.ToInt16(textBox2.Text) == (randomNumber1) - (randomNumber2))
            textBox3.Text = "Correct!";
        else if (Convert.ToInt16(textBox2.Text) == (randomNumber1) * (randomNumber2))
            textBox3.Text = "Correct!";
        else if (Convert.ToInt16(textBox2.Text) == (randomNumber1) % (randomNumber2))
            textBox3.Text = "Correct!";
        else
            textBox3.Text = "Incorrect!";



    }
}

}

我要做的是，如果你点击了按钮1，你点击了加法，点击了按钮2，你点击了减法，点击了按钮3，点击了乘法，点击了按钮4，点击了提交，它就会告诉你，你是否得到了正确的答案。我目前的答案在一定程度上做到了这一点，但如果答案是四种类型的问题中的任何一种，它就会显示为正确的。

例如:问题是8+3，你填5，它会说对，因为8-3等于5

Answer 1

你可以尝试下面的代码，你的代码有相当多的东西是多余的，并且确定用户回答是否正确的检查机制是完全错误的：

public enum Operation {
  Add,
  Subtract,
  Divide,
  Multiply,
  Modulo
}
Random rand = new Random();
private decimal GenerateQuestion(Operation o){
  int a = rand.Next(6, 11);
  int b = rand.Next(1, 6);
  decimal result = 0;
  string os = "";
  switch(o){
    case Operation.Add:          
         result = a + b;
         os = "+";
         break;
    case Operation.Subtract:
         result = a - b;
         os = "-";
         break;
    case Operation.Multiply: 
         result = a * b;
         os = "*";
         break;
    case Operation.Divide:
         result = (decimal)a/b;
         os = "/";
         break;
    case Operation.Modulo:
         result = a % b;
         os = "%";
         break;
  }
  textBox1.Text = string.Format("What is {0} {1} {2}?", a,os,b);
  return result;
}
decimal result;    
private void button1_Click(object sender, EventArgs e)
{
   result = GenerateQuestion(Operation.Add);
}
private void button2_Click(object sender, EventArgs e){
   result = GenerateQuestion(Operation.Subtract);
}
private void button3_Click(object sender, EventArgs e){
   result = GenerateQuestion(Operation.Multiply);
}
private void button4_Click(object sender, EventArgs e){
   result = GenerateQuestion(Operation.Modulo); 
}
private void button5_Click(object sender, EventArgs e){
   decimal v;
   if(decimal.TryParse(textBox2.Text, out v)){
     textBox3.Text = (v == result) ? "Correct!" : "Incorrect!";
   }else {
     textBox3.Clear();
     MessageBox.Show("Enter a number please!");
   }
}

Answer 2

您可以将一个事件处理程序分配给多个按钮，然后检查EventArgs以确定是哪个按钮触发了事件，并在其中放置了适当的条件逻辑。

不确定这是ASP.NET还是WinForms，但它的工作原理如下：

btn1.Click += button_Click;
btn2.Click += button_Click;
btn3.Click += button_Click;

 private void button_Click(object sender, EventArgs e)
 {
    var btn = sender as Button;
    if (sender != null) {
        if (btn is btn1) {
            //do something
        }
        else if (btn is btn2) {
            //do something
        }
        //etc
    }
 }

我已经以声明方式添加了事件处理程序，但您可以通过属性对话框或在标记中完成此操作。

Answer 3

您正在生成随机(*)数字来创建问题，并再次验证问题。这是完全没有意义的，因为你有一些类似“3+4是什么”的东西，并且你将结果与7 + 2或其他一些随机值进行比较。

你应该将生成的值和操作保存在一些成员变量中以供验证，或者更简单地保存预期结果。

Random random = new Random();
int expectedResult;
private void button3_Click(object sender, EventArgs e)
{
    int randomNumber1 = random.Next(6, 11);
    int randomNumber2 = random.Next(1, 6);
    textBox1.Text = "What is " + randomNumber1 + " * " + randomNumber2 + " ?";
    expectedResult = randomNumber1 * randomNumber2;
}

private void button5_Click(object sender, EventArgs e)
{  
   textBox3.Text = 
     int.Parse(textBox2.Text) == expectedResult ? "Correct!" : "Incorrect!";
}

(*)请注意，由于每次调用时的代码重新启动序列，您当前的“随机”数字并不是完全随机的-因此成对的数字将非常密切地相关。请注意，为表达式生成的数字可能与为检查生成的数字不同。正确的用法是只有一个Random对象(可能是每个线程一个对象，但对于您的情况不需要担心)。