在PHP中验证多个空字段

Question

我有以下语句来验证PHP中的空字段，它工作得很好：

if (isset($_SESSION['logged_in'])) {
if (isset($_POST['room'], $_POST['area'])) {
    $room = $_POST['room'];
    $area = $_POST['area'];

    if (empty($room) or empty($area)) {
        $error = 'Required!';
    } else {
        $query = $pdo->prepare('INSERT INTO apartments (apartments_room, apartments_area) VALUES (?, ?)');

        $query->bindValue(1, $room);
        $query->bindValue(2, $area);

        $query->execute();

        header('Location: index.php');

    }
}

我现在已经打开了更多的列在数据库中，因此也有更多的插入字段在html中进行验证。我的问题是，在这种情况下，当检查多个空字段时，我如何制定用于验证的if语句。

举个例子，这个代码不再工作了：

if (isset($_SESSION['logged_in'])) {
if (isset($_POST['room'], $_POST['area'], $_POST['rent'], $_POST['address'], $_POST['floor'], $_POST['city'], $_POST['freeFromDate'])) {
    $room = $_POST['room'];
    $area = $_POST['area'];
    $rent = $_POST['rent'];
    $address = $_POST['address'];
    $floor = $_POST['floor'];
    $city = $_POST['city'];
    $freeFromDate = $_POST['freeFromDate'];

    if (empty($room) || empty($area) ||  empty($rent) ||  empty($address) ||  empty($floor) ||  empty($city) || empty($freeFromDate)) {
        $error = 'Required!';
    } else {
        $query = $pdo->prepare('INSERT INTO apartments (apartments_room, apartments_area, apartments_rent, apartments_address, apartments_floor, apartments_city, apartments_freeFromDate) VALUES (?, ?, ?, ?, ?, ?, ?)');

        $query->bindValue(1, $room);
        $query->bindValue(2, $area);
        $query->bindValue(3, $rent);
        $query->bindValue(4, $address);
        $query->bindValue(5, $floor);
        $query->bindValue(6, $city);
        $query->bindValue(7, $freeFromDate);

        $query->execute();

        header('Location: index.php');

    }
}

这里的语法是怎么表达的？

谢谢!

Answer 1

将or更改为||

if (empty($room) || empty($area) ||  empty($rent) ||  empty($address) ||  empty($floor) ||  empty($city)) {
$error = 'Required!';

http://php.net/manual/en/language.operators.logical.php

Answer 2

这就到了脚本的可维护性和可读性差将开始产生人为错误的阶段。

在脚本的顶部创建一个更容易阅读的数组，这样您就不必在脚本中到处寻找。

$expecteds = array('room'
, 'area'
, 'rent'
,'address'
);

然后先失败：

foreach($expecteds as $expected){

if(!array_key_exists($expected, $_POST))
 exit($expected . ' is required!');

}

//从现在开始，你就知道预期的变量是存在的.

Answer 3

OR的意思与PHP中的|相同。

您应该调试var以检查是否通过了这些

"" (an empty string)
0 (0 as an integer)
0.0 (0 as a float)
"0" (0 as a string)
NULL
FALSE

如果这样做，if语句将失败，因为empty将返回true。