我正在使用一个大约800个气象站的数据集,每个气象站从1986年到2014年的月气温值。数据分为三列:(1)桩号名称、(2)日期(年和月)和(3) Temp。一般而言,数据如下所示:
STATION DATE TEMP
Station 1 198601 -15
Station 1 198602 -16
Station 1 201401 -10
Station 1 201402 -14
Station 2 198601 -11
Station 2 198602 -9
Station 2 201401 -5
Station 2 201402 -4我需要提取不同年份范围内给定月份的每个气象站的平均温度。例如,如果我需要知道1986-1990年间每个气象站7月份的平均气温。我的理想输出是一个新的列表或数据帧,它根据我指定的日期范围给出每个站点的平均温度。
我确信这可以使用for循环来完成,但我不太擅长创建这样的代码。任何建议都将不胜感激。
发布于 2014-08-29 05:13:44
使用dplyr代替数据表
weather <- data.frame(station = c("Station 1", "Station 1", "Station 1", "Station 1",
"Station 2", "Station 2", "Station 2", "Station 2"),
date = c(198601, 198602, 201401, 201402, 198601, 198602, 201401, 201402),
temp = c(-15, -16, -10, -14, -11, -9, -5, -4))
library(dplyr)
library(stringr)
# get month and year columns in data
weather <- mutate(weather,
year = str_extract(date, "\\d{4}"),
month = str_extract(date, "\\d{2}$"))
# get the mean for each station for each month
mean_station <- group_by(weather, station, month) %>%
summarise(mean_temp = mean(temp, na.rm = T))如果只需要在特定的日期范围内执行此操作,则可以按年份添加筛选器
mean_station <- group_by(weather, station, month) %>%
filter(year >= 1986, year <= 2015) %>%
summarise(mean_temp = mean(temp, na.rm = T))发布于 2014-08-29 05:03:33
像这样的东西...?
> df$month <- substr(df$DATE, 5, 6)
> result <- aggregate(TEMP~STATION+month, mean, data=df)
> data.frame(Year=unique(substr(df$DATE, 1, 4)), result)
Year STATION month TEMP
1 1986 Station1 01 -12.5
2 2014 Station2 01 -8.0
3 1986 Station1 02 -15.0
4 2014 Station2 02 -6.5发布于 2014-08-29 05:07:49
或者也许
library(data.table)
setDT(df)[, list(MeanTemp = mean(TEMP)),
by = list(STATION, Mon = substr(DATE, 5, 6))]
# STATION Mon MeanTemp
# 1: Station 1 01 -12.5
# 2: Station 1 02 -15.0
# 3: Station 2 01 -8.0
# 4: Station 2 02 -6.5https://stackoverflow.com/questions/25557848
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