当我关闭Pygame屏幕时它会冻结

Question

代码加载了一个pygame屏幕窗口，但当我单击X关闭它时，它变得没有响应。我在64位系统上运行，使用的是32位python和32位pygame。

from livewires import games, color

games.init(screen_width = 640, screen_height = 480, fps = 50)

games.screen.mainloop()

Answer 1

Mach1723的answer是正确的，但我想建议主循环的另一个变体：

while 1:
    for event in pygame.event.get():
        if event.type == QUIT: ## defined in pygame.locals
            pygame.quit()
            sys.exit()

        if event.type == ## Handle other event types here...

    ## Do other important game loop stuff here.

Answer 2

我推荐下面的代码。首先，它包括时钟，这样你的程序就不会消耗CPU，除了轮询事件之外什么也不做。其次，它调用pygame.quit()来防止程序在windows的IDLE下运行时冻结。

# Sample Python/Pygame Programs
# Simpson College Computer Science
# http://cs.simpson.edu/?q=python_pygame_examples

import pygame

# Define some colors
black    = (   0,   0,   0)
white    = ( 255, 255, 255)
green    = (   0, 255,   0)
red      = ( 255,   0,   0)

pygame.init()

# Set the height and width of the screen
size=[700,500]
screen=pygame.display.set_mode(size)

pygame.display.set_caption("My Game")

#Loop until the user clicks the close button.
done=False

# Used to manage how fast the screen updates
clock=pygame.time.Clock()

# -------- Main Program Loop -----------
while done==False:
    for event in pygame.event.get(): # User did something
        if event.type == pygame.QUIT: # If user clicked close
            done=True # Flag that we are done so we exit this loop

    # Set the screen background
    screen.fill(black)

    # Limit to 20 frames per second
    clock.tick(20)

    # Go ahead and update the screen with what we've drawn.
    pygame.display.flip()

# Be IDLE friendly. If you forget this line, the program will 'hang'
# on exit.
pygame.quit ()

Answer 3

这是一个非常简单的问题，您需要处理"QUIT“事件，请参阅事件文档：http://www.pygame.org/docs/ref/event.html

编辑:我现在想到你可能正在处理"QUIT“事件，它不工作，但没有更多的细节到你的代码，我不知道。

下面是一个处理"QUIT“事件的简单方法的快速示例：

import sys
import pygame

# Initialize pygame
pygame.init()
pygame.display.set_mode(resolution=(640, 480))

# Simple(ugly) main loop
curEvent = pygame.event.poll()

while curEvent.type != pygame.QUIT:
      # do something
      curEvent = pygame.event.poll()