从逻辑上讲,在SQL中,我们可以使用连接从表中删除数据,例如
DELETE clb_subscriber_group_mapping .* FROM clb_subscriber_group_mapping
INNER JOIN clb_driver_group ON (clb_driver_group.id = clb_subscriber_group_mapping.driver_group_id)
INNER JOIN clb_company ON (clb_company.id = clb_driver_group.company_id)
WHERE clb_company.id = 256 AND clb_subscriber_group_mapping.subscriber_id = 1784;上述查询的CodeIgniter等效项是什么?
CodeIgniter是否支持使用joins删除查询?
发布于 2012-05-14 18:14:43
你必须使用Active Records吗?
下面的query将做不同的事情。
$int_company_id = 256;
$int_subscriber_id = 1784;
$this->db->query("
DELETE clb_subscriber_group_mapping .* FROM clb_subscriber_group_mapping
INNER JOIN clb_driver_group ON (clb_driver_group.id = clb_subscriber_group_mapping.driver_group_id)
INNER JOIN clb_company ON (clb_company.id = clb_driver_group.company_id)
WHERE clb_company.id = ? AND clb_subscriber_group_mapping.subscriber_id = ?;
", array($int_company_id, $int_subscriber_id));发布于 2012-05-14 18:48:24
使用CodeIgniter的活动记录类不能做到这一点。它不支持delete查询中的连接。您必须使用Robin Castlin提到的$this->db->query()执行查询。
下面的代码取自核心文件。它是生成DELETE查询的内部组件之一。
function _delete($table, $where = array(), $like = array(), $limit = FALSE)
{
$conditions = '';
if (count($where) > 0 OR count($like) > 0)
{
$conditions = "\nWHERE ";
$conditions .= implode("\n", $this->ar_where);
if (count($where) > 0 && count($like) > 0)
{
$conditions .= " AND ";
}
$conditions .= implode("\n", $like);
}
$limit = ( ! $limit) ? '' : ' LIMIT '.$limit;
return "DELETE FROM ".$table.$conditions.$limit;
}正如您所看到的,其中没有指定插入JOIN子句的内容。
发布于 2017-01-25 22:38:10
我也遇到了同样的问题,连接被忽略了:
$r1 = $db->where("object2_type", $object_type)
->join($object_type, "$object_type.id = object1_id", "LEFT")
->where("$object_type.id IS NULL", null, false)
->delete("knots");所以我是这样做的:
$ids = $db->select("knots.id")
->where("object2_type", $object_type)
->join($object_type, "$object_type.id = object1_id", "LEFT")
->where("$object_type.id IS NULL", null, false)
->get("knots")->result_object();
/* my ow function which generates a string like '1','2','3' or 0 */
$ids_csv = $this->mh()->get_flat_items_as_csv($ids);
$r = $db->where("knots.id IN ($ids_csv)", null, false)->delete("knots);https://stackoverflow.com/questions/10581239
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