我有数百个cisco配置文件,我需要(通过python)查找(通过python)具有特定服务策略的接口,在本例中为WIRELESS-IN。我用来捕获接口的正则表达式是: pat=re.compile('( interface .*?)!$',re.DOTALL|re.M)
在这种情况下,我需要返回FastEthernet1/0/2。
示例数据可能如下所示:
我有一个正则表达式来将Interface元素匹配到一个组中,但不知道如何在该组中查找。有人能帮上忙吗?
interface FastEthernet1/0/1
description Foo
switchport access vlan 300
switchport mode access
switchport port-security aging time 2
no logging event link-status
speed 100
duplex full
priority-queue out
mls qos trust dscp
no snmp trap link-status
no cdp enable
spanning-tree portfast
hold-queue 120 in
hold-queue 200 out
ip dhcp snooping trust
!
interface FastEthernet1/0/2
description wlap2
switchport access vlan 100
switchport mode access
switchport port-security maximum 15
switchport port-security
switchport port-security aging time 2
switchport port-security aging type inactivity
ip access-group 100 in
no logging event link-status
srr-queue bandwidth shape 0 0 0 10
queue-set 2
priority-queue out
no snmp trap link-status
storm-control broadcast level pps 100 50
storm-control multicast level pps 100 50
storm-control action trap
spanning-tree portfast
spanning-tree bpduguard enable
service-policy input WIRELESS_IN
ip dhcp snooping limit rate 15
!
interface FastEthernet1/0/3
description Test3
switchport access vlan 199
switchport mode access
switchport port-security aging time 2
no logging event link-status
queue-set 2
priority-queue out
mls qos trust dscp
no snmp trap link-status
no cdp enable
spanning-tree portfast
service-policy input VOICE-LAN我拼凑了这段代码:
import re,string
f = open("sampleconfig.cfg")
cfgdata = f.read()
pat=re.compile('(interface.*?)!$',re.DOTALL|re.M)
pat2 = re.compile("service-policy.input.WIRELESS-IN")
data = pat.findall(cfgdata)
i=0
while i < len(data):
if pat2.findall(data[i]):
print (data[i].split("\n")[0])
i = i+1
else:
i = i+1
pass发布于 2014-09-16 20:42:40
这是否是一种更好的方式还存在争议,但至少有一些不同:
import re,string
f = open("sampleconfig.cfg")
cfgdata = f.read()
pat = '(?sm)interface (\S*)(?:(?!^!$).)*service-policy.input.WIRELESS_IN.*?!$'
data = re.findall(pat, cfgdata)发布于 2019-11-23 18:40:20
解决此任务的另一种方法是使用TTP模块(我是该模块的作者)与匹配结果过滤,例如以下代码:
my_template="""
<group
name="interfaces_with_WIRELESS-IN_policy.{{ interface }}" functions="contains(policy)">
interface {{ interface }}
service-policy input {{ policy | equal(WIRELESS_IN) }}
</group>
"""
from ttp import ttp
parser = ttp(template=my_template)
parser.parse()
print(parser.result(format="json")[0])将产生以下结果:
[
{
"interfaces_with_WIRELESS-IN_policy": {
"FastEthernet1/0/2": {
"policy": "WIRELESS_IN"
}
}
}
]如何工作
TTP解析OP提供的文本数据,以提取接口和附加到它们的策略,而不进行任何过滤,将产生以下结果:
[
{
"interfaces_with_WIRELESS-IN_policy": {
"FastEthernet1/0/1": {},
"FastEthernet1/0/2": {
"policy": "WIRELESS_IN"
},
"FastEthernet1/0/3": {
"policy": "VOICE-LAN"
}
}
}
]但是通过使用匹配变量函数" equal“,我们可以指示TTP使不等于"WIRELESS_IN”的匹配结果无效,另外,在为group定义functions="contains(policy)“后,TTP将检查组结果(这是python字典)是否有名为"policy”的键,从而使没有这样的键的组匹配结果无效。
但是,上面的代码不会生成接口列表(根据OP的请求),直到您再应用一个TTP组函数- "itemize“-它将根据组结果创建一个项目列表,例如模板:
my_template="""
<group
name="interfaces_with_WIRELESS-IN_policy" functions="contains(policy) | itemize(interface)">
interface {{ interface }}
service-policy input {{ policy | equal(WIRELESS_IN) }}
</group>
"""将发出以下结果:
[
{
"interfaces_with_WIRELESS-IN_policy": [
"FastEthernet1/0/2"
]
}
]发布于 2013-10-02 00:56:38
import re,string
f = open("sampleconfig.cfg")
cfgdata = f.read()
pat=re.compile('(interface.*?)!$',re.DOTALL|re.M)
pat2 = re.compile("service-policy.input.WIRELESS-IN")
data = pat.findall(cfgdata)
i=0
while i < len(data):
if pat2.findall(data[i]):
print (data[i].split("\n")[0])
i = i+1
else:
i = i+1
passhttps://stackoverflow.com/questions/19101596
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