blocks|key|2107293|text|Bah+-I可以在5个字符内使C崩溃：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2107294|main;|code-block|syntax|javascript|2107295|这将声明一个名为‘int’的隐式主变量。它是全局变量，因此该变量的初始值为0。它是C，名称没有修饰-所以链接器不会意识到它是一个变量，而不是一个函数。|offset|length|style|CODE|2107296|GCC给了我一个警告--但仅此而已。|2107297|$+gcc+crash.c+
crash.c:1:+warning:+data+definition+has+no+type+or+storage+class
$+./a.exe
Segmentation+fault+(core+dumped)
$|2107298|entityMap^0|0|0|9|3|11|1|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]|$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|R|$]]

Bah - I can crash C in 5 characters:

<pre><code>main;
</code></pre>

This declares an implicit <code>int</code> variable called 'main'.
It's global so the variable has an initial value of <code>0</code>.
It's C the names aren't decorated - so the linker doesn't realize that it's a var and not a function.

GCC gave me a warning - but that's all.

<pre><code>$ gcc crash.c 
crash.c:1: warning: data definition has no type or storage class
$ ./a.exe
Segmentation fault (core dumped)
$
</code></pre>

blocks|key|5084030|text|带有0字符的崩溃：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5084031|$+>+golf.c
$+gcc+-Wl,--defsym=main=0+golf.c
$+./a.out
Segmentation+fault|code-block|syntax|javascript|5084032|entityMap^0|2|1|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Crash with <code>0</code> characters:

<pre><code>$ &gt; golf.c
$ gcc -Wl,--defsym=main=0 golf.c
$ ./a.out
Segmentation fault
</code></pre>

blocks|key|2970761|text|我想知道这算不算...|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2970762|a|code-block|syntax|javascript|2970763|这是在JavaScript中。这会导致运行时错误为"object+not+found“。由于JavaScript是一种动态语言，因此在语法上这实际上是正确的。仍然感觉像是在扭曲规则。:P|offset|length|style|BOLD|2970764|entityMap^0|0|0|J|3|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I wonder if this counts...

<pre><code>a
</code></pre>

This is in JavaScript. This gives the runtime error of "object not found". Since JavaScript is a dynamic language, syntactically this is actually correct. Still feels like twisting the rules. :P

blocks|key|195110|text|使用python：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|195111|1/0|code-block|syntax|javascript|195112|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

using python:

<pre><code>1/0
</code></pre>

blocks|key|5084235|text|X86机器码:1字节|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5084236|从windows中的命令提示符创建包含字节F4的文件a.com，x86+halt指令：|5084237|F:\>debug
-a+100
0BFD:0100+hlt
0BFD:0101
-r+cx
CX+0000
:1
-n+a.com
-w
Writing+00001+bytes
-q

F:\>a.com|code-block|syntax|javascript|5084238|NTVDM+CPU遇到非法指令|5084239|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<h2>X86 machine code: 1 byte</h2>

From cmd prompt in windows create file a.com containing byte F4, x86 halt instruction:

<pre><code>F:\&gt;debug
-a 100
0BFD:0100 hlt
0BFD:0101
-r cx
CX 0000
:1
-n a.com
-w
Writing 00001 bytes
-q

F:\&gt;a.com
</code></pre>

The NTVDM CPU has encountered illegal instruction

blocks|key|2101278|text|$+cat+>+crash.S
hlt
$+as+-o+crash.o+crash.S
$+ld+crash.o
ld:+warning:+cannot+find+entry+symbol+_start;+defaulting+to+0000000008048054
$+./a.out
Segmentation+fault|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2101279|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$ cat &gt; crash.S
hlt
$ as -o crash.o crash.S
$ ld crash.o
ld: warning: cannot find entry symbol _start; defaulting to 0000000008048054
$ ./a.out
Segmentation fault
</code></pre>

blocks|key|193441|text|Commodore+64+BASIC：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|193442|poke+2,2:sys2|code-block|syntax|javascript|193443|或更短(使用PETSCII+graphic-Char键)：|193444|pO2,2:sY2|193445|(崩溃：$02+MOS/CSG6510上的无效操作码)。实际上它可以在7个字节(3条指令)中完成：|193446|lda+#$02
sta+$02
jmp+$0002|193447|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Commodore 64 BASIC:

<pre><code>poke 2,2:sys2
</code></pre>

or shorter (using PETSCII graphic-char shortcuts):

<pre><code>pO2,2:sY2
</code></pre>

(crash: $02 invalid opcode on MOS/CSG6510). Actually it can be done in 7 bytes (3-instructions):

<pre><code>lda #$02
sta $02
jmp $0002
</code></pre>

blocks|key|2107454|text|如果你在一家有TI-89的电脑商店，你可以通过键入以下命令来使其崩溃：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2107455|Exec+"00000000"|code-block|syntax|javascript|2107456|(这是8个零)|2107457|它会产生“非法指令”。按2nd%2BLeft%2BRight%2BON键重置计算器。|2107458|如果你想获得更多的乐趣，可以这样做：|2107459|Exec+"4E4A4E750000"|2107460|这将启动隐藏的硬件测试菜单，包括内存测试、LCD测试(绘制棋盘等)。还有更多。不幸的是，状态栏被擦除了，而且calc的操作系统中没有任何东西将其拉回来，所以要自行清理，请按照上面的说明进行重置，或者执行以下操作：|2107461|Exec+"307C56E670FF20C020C020C020C020C04E750000"|2107462|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

If you're at a computer store that has TI-89s, you can crash one by typing this in:

<pre><code>Exec "00000000"
</code></pre>

(that's 8 zeros)

It will yield "Illegal Instruction". Press 2nd+Left+Right+ON to reset the calc.

If you want to have more fun, do this:

<pre><code>Exec "4E4A4E750000"
</code></pre>

That launches the hidden hardware test menu, including memory tests, LCD tests (draws checkerboards et al.) and more. Unfortunately, the status bar gets erased, and nothing in the calc's OS draws it back, so to clean up after yourself, reset per the instructions above, or do this:

<pre><code>Exec "307C56E670FF20C020C020C020C020C04E750000"
</code></pre>

blocks|key|2970877|text|大脑*ck|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2970878|5个字符|2970879|%2B[>%2B]|code-block|syntax|javascript|2970880|这将需要一段时间，但最终程序将耗尽内存并不可避免地崩溃。|2970881|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<h1>Brainf*ck</h1>

<h2>5 characters</h2>

<pre><code>+[&gt;+]
</code></pre>

It will take it a while, but eventually the program will run out of memory and inevitably crash.

blocks|key|5083882|text|那java+Z呢？如果不存在文件，它将使用java.lang.NoClassDefFoundError“崩溃”。所以我的答案是零个字母。如果这是无效的，那么.|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5083883|class+T{}|code-block|syntax|javascript|5083884|会在线程"+main“java.lang.NoSuchMethodError:+main中出现$+java+T异常而”崩溃“|5083885|如果你想要实际运行的东西，那么如果你愿意滥用一些东西|5083886|class+T{static+{int+i+=1/0;}}|5083887|否则|5083888|class+T{public+static+void+main(String[]a){main(a);}}|5083889|entityMap^0|1|6|L|U|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|13|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|Q|3|R|5|6|7|15|8|@]|D|@]|E|$]]|$1|S|3|T|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|U|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|V|$]]

How about <code>java Z</code>? If no file exists it will "crash" with a <code>java.lang.NoClassDefFoundError</code>. So my answer is zero letters. If that is not valid then...

<pre><code>class T{}
</code></pre>

Would "crash" with
 $ java T
Exception in thread "main" java.lang.NoSuchMethodError: main

If you want something that actually runs, then if you are willing to abuse things a little

<pre><code>class T{static {int i =1/0;}}
</code></pre>

Else 

<pre><code>class T{public static void main(String[]a){main(a);}}
</code></pre>

blocks|key|2107430|text|引用this+answer|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2107431|2107432|所有这些答案，而不是Befunge？我敢打赌，这是所有解决方案中最短的：|blockquote|2107433|2107434|1|2107435|不是开玩笑。你自己试试吧：http://www.quirkster.com/js/befunge.html|2107436|编辑:我想我需要解释一下这个问题。1操作数将1推送到Befunge的内部堆栈，缺少其他操作数将其放入该语言规则下的循环中。|2107437|使用提供的解释器，您最终会--我的意思是最终--到达一个点，即表示Befunge堆栈的Javascript数组变得太大，浏览器无法重新分配。如果你有一个简单的Befunge解释器，它有一个更小的有界堆栈--就像下面的大多数语言一样--这个程序会导致更快的溢出。|2107438|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/62188/stack-overflow-code-golf|http://www.quirkster.com/js/befunge.html^0|2|B|0|0|0|0|0|0|D|14|1|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]|$1|D|3|-4|5|6|7|13|8|@]|9|@]|C|$]]|$1|E|3|F|5|G|7|14|8|@]|9|@]|C|$]]|$1|H|3|-4|5|6|7|15|8|@]|9|@]|C|$]]|$1|I|3|J|5|6|7|16|8|@]|9|@]|C|$]]|$1|K|3|L|5|6|7|17|8|@]|9|@$A|18|B|19|1|1A]]|C|$]]|$1|M|3|N|5|6|7|1B|8|@]|9|@]|C|$]]|$1|O|3|P|5|6|7|1C|8|@]|9|@]|C|$]]|$1|Q|3|-4|5|6|7|1D|8|@]|9|@]|C|$]]]|R|$S|$5|T|U|V|C|$W|X]]|J|$5|T|U|V|C|$W|Y]]]]

to quote <a href="https://stackoverflow.com/questions/62188/stack-overflow-code-golf">this answer</a>:

<blockquote>
 All these answers and no Befunge? I'd
 wager a fair amount it's shortest
 solution of them all:

<pre><code>1
</code></pre>
 
 Not kidding. Try it yourself:
 <a href="http://www.quirkster.com/js/befunge.html" rel="nofollow noreferrer">http://www.quirkster.com/js/befunge.html</a>
 
 EDIT: I guess I need to explain this
 one. The 1 operand pushes a 1 onto
 Befunge's internal stack and the lack
 of anything else puts it in a loop
 under the rules of the language.
 
 Using the interpreter provided, you
 will eventually--and I mean
 eventually--hit a point where the
 Javascript array that represents the
 Befunge stack becomes too large for
 the browser to reallocate. If you had
 a simple Befunge interpreter with a
 smaller and bounded stack--as is the
 case with most of the languages
 below--this program would cause a more
 noticeable overflow faster.
</blockquote>

blocks|key|2970639|text|在C中，20个字符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2970640|void+main(){main();}|code-block|syntax|javascript|2970641|更新:由roe建议，15个字符：|2970642|main(){main();}|2970643|注:使用VC%2B%2B+2008进行了测试。|2970644|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

In C, 20 characters:

<pre><code>void main(){main();}
</code></pre>

Update: Suggested by roe, 15 characters:

<pre><code>main(){main();}
</code></pre>

Note: Tested with VC++ 2008.

blocks|key|5084320|text|很晚了，但不管怎样。PHP，32个字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5084321|$r=function($z){$z($z);};$r($r);|code-block|syntax|javascript|5084322|提供Fatal+error:+Allowed+memory+size+of+134217728+bytes+exhausted+(tried+to+allocate+261900+bytes)+in+...|offset|length|style|CODE|5084323|从技术上讲，我也可以在29分钟内完成|5084324|$r=function($z){$z();};$r(0);|5084325|但这并不像无限递归那么有趣。因此，我认为“未定义的函数”错误不应算作脚本语言中的“编译”，否则：|5084326|Z();|5084327|将是最小的解决方案。|5084328|此外，如果(作为脚本)超过最大执行时间，而不是崩溃，该怎么办?8个字符：|5084329|for(;;);|5084330|我最初的理解是在for循环的第三个表达式中有一个$i%2B%2B，但是因为PHP将所有的整数都视为有符号的，而不是溢出，所以它变成了负数。|5084331|entityMap^0|0|0|2|2T|0|0|0|0|0|0|0|0|O|4|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|16|8|@$I|17|J|18|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|19|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|1A|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|1B|8|@]|9|@]|A|$]]|$1|S|3|T|5|D|7|1C|8|@]|9|@]|A|$E|F]]|$1|U|3|V|5|6|7|1D|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|1E|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|D|7|1F|8|@]|9|@]|A|$E|F]]|$1|10|3|11|5|6|7|1G|8|@$I|1H|J|1I|K|L]]|9|@]|A|$]]|$1|12|3|-4|5|6|7|1J|8|@]|9|@]|A|$]]]|13|$]]

Late, but whatever. PHP, 32 characters.

<pre><code>$r=function($z){$z($z);};$r($r);
</code></pre>

gives <code>Fatal error: Allowed memory size of 134217728 bytes exhausted (tried to allocate 261900 bytes) in ...</code>

Technically, I could also do it in 29 with

<pre><code>$r=function($z){$z();};$r(0);
</code></pre>

But that isn't as much fun as infinite recursion. That, and I don't think "undefined function" errors should count as "compiling" in a scripting language, otherwise:

<pre><code>Z();
</code></pre>

would be the smallest solution.

Also, instead of crashing, how about (as a script) surpassing max execution time? 8 chars:

<pre><code>for(;;);
</code></pre>

My original take on that had a <code>$i++</code> in the third expression of the for loop, but because PHP treats all integers as signed, instead of overflowing, it just goes negative.

blocks|key|193209|text|在程序集中尝试以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|193210|push+0
ret|code-block|syntax|javascript|193211|当然，将所有其他垃圾代码添加到一个应用程序中。|193212|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Try this in assembly:

<pre><code>push 0
ret
</code></pre>

of course add the all other garbage to compile into an application.

blocks|key|2101296|text|在windows+powershell中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2101297|throw|code-block|syntax|javascript|2101298|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

in windows powershell:

<pre><code>throw
</code></pre>

blocks|key|2101418|text|方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2101419|(1)|code-block|syntax|javascript|2101420|填充文本以使其更长。|2101421|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Scheme:

<pre><code>(1)
</code></pre>

Filler text to make this longer.

blocks|key|2970566|text|在C中，33个字符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2970567|int+main(void){return*((int*)0);}|code-block|syntax|javascript|2970568|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In C, 33 characters:

<pre><code>int main(void){return*((int*)0);}
</code></pre>

blocks|key|5083832|text|在QBasic中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5083833|?+1/0|code-block|syntax|javascript|5083834|(至少我认为它仍然会编译，然后被零除；已经有相当长的一段时间了……)|5083835|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

In QBasic:

<pre><code>? 1/0
</code></pre>

(At least I think it'll still compile and then crash with divide-by-zero; it's been quite some time...)

blocks|key|195300|text|main+=+undefined|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|195301|在哈斯克尔。|unstyled|195302|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>main = undefined
</code></pre>

In Haskell.

blocks|key|195166|text|F#+3个字符|type|unstyled|depth|inlineStyleRanges|entityRanges|data|195167|1/0|195168|进行编译，但会给出一个警告。|195169|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

<h2>F# 3 characters</h2>

1/0

Does compile, though gives a warning.

blocks|key|2971095|text|F#，11个字符|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2971096|box+0+:?>+unit|code-block|syntax|javascript|2971097|编译时不会发出警告。崩溃:+System.InvalidCastException:无法将'System.Int32‘类型的对象强制转换为'Microsoft.FSharp.Core.Unit’类型。|2971098|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

<h2>F#, 11 characters</h2>

<pre><code>box 0 :?&gt; unit
</code></pre>

Compiles without a warning. Crashes with:
System.InvalidCastException: Unable to cast object of type 'System.Int32' to type 'Microsoft.FSharp.Core.Unit'.

blocks|key|5084339|text|PostScript，1个字符|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|5084340|像GolfScript一样：|5084341|*|code-block|syntax|javascript|5084342|语法上合法，但在运行时会崩溃，因为没有定义令牌*+(与GolfScript崩溃的原因不同)。|CODE|5084343|entityMap^0|0|F|0|0|0|N|1|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|U|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|V|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|W|8|@$9|X|A|Y|B|O]]|D|@]|E|$]]|$1|P|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|Q|$]]

<h1>PostScript, 1 character</h1>

Like GolfScript:

<pre><code>*
</code></pre>

Syntactically legal, but crashes during runtime because the token <code>*</code> is not defined (different reason than why GolfScript crashes).

blocks|key|5083731|text|int+main+()+{+int+n+=+0;+return+1+/+n;+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|5083732|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>int main () { int n = 0; return 1 / n; }
</code></pre>

blocks|key|2970672|text|它取决于线程允许的最大堆栈大小。但当使用VC9编译时，它确实会崩溃：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2970673|int+main()
{
++++int+a[10000000];
++++return+0;
};|code-block|syntax|javascript|2970674|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

It depends upon the allowed max stack size for a thread. But it does crash when compiled using VC9:

<pre><code>int main()
{
 int a[10000000];
 return 0;
};
</code></pre>

blocks|key|193370|text|Perl|type|unstyled|depth|inlineStyleRanges|entityRanges|data|193371|3个字符|193372|1/0|code-block|syntax|javascript|193373|产生：|193374|Illegal+division+by+zero+at+crash.pl+line+1.|193375|(仍然在寻找可以在两个时间内完成的东西。)|193376|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

<h1>Perl</h1>

<h2>3 characters</h2>

<pre><code>1/0
</code></pre>

Produces:

<pre><code>Illegal division by zero at crash.pl line 1.
</code></pre>

(still looking for something that will do it in two..)

blocks|key|2971002|text|C#，37个字符|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2971003|class+F{static+void+Main(){Main();}}|code-block|syntax|javascript|2971004|分解堆栈。|2971005|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

C#, 37 chars

<pre><code>class F{static void Main(){Main();}}
</code></pre>

Explodes stack.

blocks|key|193462|text|Befunge，1个字符|type|unstyled|depth|inlineStyleRanges|entityRanges|data|193463|pace+RCIX，来自最短程序溢出堆栈What's+the+shortest+code+to+cause+a+stack+overflow?的几个答案也适用；最短的是befunge程序：|offset|length|193464|1|code-block|syntax|javascript|193465|PS:+Golfscript，没有简短的答案|193466|看起来golfscript+http://www.golfscript.com/在这方面做得不好:我假设会有一个单字符的堆栈下溢或堆栈溢出，但它似乎被设计成不会崩溃。希望更了解这门语言的人能填写更多细节。|193467|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/62188/stack-overflow-code-golf|http://www.golfscript.com/^0|0|K|1F|0|0|0|0|E|Q|1|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Y|8|@]|9|@$D|Z|E|10|1|11]]|A|$]]|$1|F|3|G|5|H|7|12|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|13|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|14|8|@]|9|@$D|15|E|16|1|17]]|A|$]]|$1|O|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]|G|$5|R|S|T|A|$U|W]]]]

<h2>Befunge, 1 character</h2>

pace RCIX, several answers from the shortest program to overflow the stack <a href="https://stackoverflow.com/questions/62188/stack-overflow-code-golf">What&#39;s the shortest code to cause a stack overflow?</a> also apply; the shortest is the befunge program:

<pre><code>1
</code></pre>

<h2>PS: Golfscript, no short answer</h2>

It seems golfscript <a href="http://www.golfscript.com/" rel="nofollow noreferrer">http://www.golfscript.com/</a> is bad at this: I assumed there'd be a one-character stack-underflow or stack-overflow, but it seems designed not to crash. Hopefully someone who knows the language better will fill in more details.

blocks|key|5084333|text|0字节|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|5084334|使用A86，你可以拥有一个零大小的源文件！|5084335|使用DOS命令提示符：|5084336|>+copy+con+crash.asm
[ctrl-z]
1+file(s)+copied
>+dir+*.asm
11/12/2009++13:59+++++++++++++++++0+crash.asm
>+a86+crash.asm
A86+macro+assembler,+V4.05+Copyright+2000+Eric+Isaacson
Source:
crash.asm
Object:+crash.COM
Symbols:+crash.SYM
>+dir+*.com
11/12/2009++13:59+++++++++++++++++0+CRASH.COM
>+c.com|code-block|syntax|javascript|5084337|entityMap^0|0|3|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|T|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|U|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|V|8|@]|D|@]|E|$M|N]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

0 Bytes

Using A86, you can have a zero sized source file! 

Using the DOS command prompt:

<pre><code>&gt; copy con crash.asm
[ctrl-z]
1 file(s) copied
&gt; dir *.asm
11/12/2009 13:59 0 crash.asm
&gt; a86 crash.asm
A86 macro assembler, V4.05 Copyright 2000 Eric Isaacson
Source:
crash.asm
Object: crash.COM
Symbols: crash.SYM
&gt; dir *.com
11/12/2009 13:59 0 CRASH.COM
&gt; c.com
</code></pre>

blocks|key|193469|text|Groovy+3个字符|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|193470|1/0|code-block|syntax|javascript|193471|产生|193472|193473|+java.lang.ArithmeticException:+/+by+zero|blockquote|193474|193475|entityMap^0|0|B|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|W|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|X|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]|$1|N|3|O|5|P|7|Z|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|10|8|@]|D|@]|E|$]]|$1|R|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|S|$]]

Groovy 3 characters

<pre><code>1/0
</code></pre>

Produces

<blockquote>
 java.lang.ArithmeticException: / by
 zero
</blockquote>

blocks|key|195304|text|NASM|type|unstyled|depth|inlineStyleRanges|entityRanges|data|195305|mov+al,+[0]|offset|length|style|CODE|195306|$+nasm+-f+elf64+-o+crash.o+crash.asm
$+ld+-o+crash+crash.o
$+./crash|code-block|syntax|javascript|195307|entityMap^0|0|0|B|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|S|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

<h1>NASM</h1>
<code>mov al, [0]</code>
<pre><code>$ nasm -f elf64 -o crash.o crash.asm
$ ld -o crash crash.o
$ ./crash
</code></pre>

This is a little bit of fun. Can you devise the shortest program which compiles but does nothing but immediately crash when executed? Wherefore by "crash" we mean that the program stops with an error condition (a core dump for example).

Is there a language that crashes faster (7 chars) than C using a gcc compiler? [I leave this answer for somebody to find.]

(It should be allowable to use compiler flags. Otherwise 7 wouldn't work nowadays, compiler checks became much better.)

[evaluation of results] I am unable to mark a single answer because there are multiple correct ones for multiple languages. It would not be fair to disqualify one answer for another. Please use votes for choosing best answers.

Code-Golf: What is the shortest program that compiles and crashes?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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功能1上新10个字符

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功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符。

功能5描述100个字符功能5描述100个字符功能5描述100个字符功能5描述100个字符功能5描述100个字符功能5描述100个字符

功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符

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这是一个小小的乐趣。你能设计出一个最短的程序，它可以编译，但在执行时什么也不做，只会立即崩溃？因此，我们所说的“崩溃”是指程序由于错误条件(例如核心转储)而停止。有没有一种语言比使用gcc编译器的C崩溃更快(7个字符)？我把这个答案留给别人去找。(应该允许使用编译器标志。否则7现在不能工作了，编译器检查变得更好了。)结果评估我无法标记单个答案，因为多个语言有多个正确答案。取消一个答案与另一个答案的

问Code-Golf:编译并崩溃的最短程序是什么？
EN

回答 30

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