blocks|key|94963|text|AFAIK，没有正常的方法可以做到这一点。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|94964|如果你真的想要，这里有个小技巧。Eclipse文件是一个非常简单的.classpath。您可以编写一个遍历目录、更新.classpath+xml并刷新项目的脚本或ant任务。|94965|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

AFAIK, there's no normal way to do this.

If you really want, there's a little hack.
Eclipse .classpath file is a very simple XML.
You can write a script or ant task that goes over a directory, updates .classpath xml and refreshes the project.

blocks|key|4881771|text|使用自制的“Eclipse”解决了这个问题，但需要您构建一个ClassPath插件：http://www.ibm.com/developerworks/edu/os-dw-os-eclipse-classpath.html|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4881772|entityMap|0|LINK|mutability|MUTABLE|url|http://www.ibm.com/developerworks/edu/os-dw-os-eclipse-classpath.html^0|16|1X|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Using a homemade "ClassPath Container" solves the problem but needs you to build an Eclipse-plugin : <a href="http://www.ibm.com/developerworks/edu/os-dw-os-eclipse-classpath.html" rel="noreferrer">http://www.ibm.com/developerworks/edu/os-dw-os-eclipse-classpath.html</a>

blocks|key|2006651|text|我的同事实现了一个类路径容器，它递归地查找工作区中给定目录中的jars，看看http://openscada.org/2010/05/31/adding-a-directory-as-class-path-to-eclipse/|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2006652|更新站点可在http://repo.openscada.org/p2/bob/R上找到|2006653|该插件在LGPL+V3下获得许可，您可以在https://github.com/ctron/org.openscada.bob下找到源代码。|2006654|entityMap|0|LINK|mutability|MUTABLE|url|http://openscada.org/2010/05/31/adding-a-directory-as-class-path-to-eclipse/|1|http://repo.openscada.org/p2/bob/R|2|https://github.com/ctron/org.openscada.bob^0|12|24|0|0|6|Y|1|0|L|16|2|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@$A|U|B|V|1|W]]|C|$]]|$1|D|3|E|5|6|7|X|8|@]|9|@$A|Y|B|Z|1|10]]|C|$]]|$1|F|3|G|5|6|7|11|8|@]|9|@$A|12|B|13|1|14]]|C|$]]|$1|H|3|-4|5|6|7|15|8|@]|9|@]|C|$]]]|I|$J|$5|K|L|M|C|$N|O]]|P|$5|K|L|M|C|$N|Q]]|R|$5|K|L|M|C|$N|S]]]]

My colleague implemented a classpath container which recursivly looks for jars in a given directory within the workspace, have a look at <a href="http://openscada.org/2010/05/31/adding-a-directory-as-class-path-to-eclipse/" rel="nofollow noreferrer">http://openscada.org/2010/05/31/adding-a-directory-as-class-path-to-eclipse/</a>

The update site can be found at <a href="http://repo.openscada.org/p2/bob/R" rel="nofollow noreferrer">http://repo.openscada.org/p2/bob/R</a>

The plugin is licensed unter LGPL V3 and you can find the source code under <a href="https://github.com/ctron/org.openscada.bob" rel="nofollow noreferrer">https://github.com/ctron/org.openscada.bob</a>

blocks|key|4881806|text|使用Maven2，并使用Eclipse+Maven2插件。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4881807|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Use Maven2, and use the Eclipse Maven2 plugin.

blocks|key|93297|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|93298|表示将新的.jar文件添加到此目录(并刷新项目)会更新构建路径|blockquote|93299|93300|93301|对不起，Eclipse不支持这一点。|93302|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|-4|4|5|6|J|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|K|7|@]|8|@]|9|$]]|$1|D|3|-4|4|5|6|L|7|@]|8|@]|9|$]]|$1|E|3|-4|4|5|6|M|7|@]|8|@]|9|$]]|$1|F|3|G|4|5|6|N|7|@]|8|@]|9|$]]|$1|H|3|-4|4|5|6|O|7|@]|8|@]|9|$]]]|I|$]]

<blockquote>
 Meaning that adding a new .jar file to
 this directory (and refreshing the
 project) updates the buildpath
</blockquote>

Sorry, Eclipse doesn't support this.

blocks|key|93347|text|在windows机器上，你可以像uzhin所说的那样，在命令行中使用一行一行命令。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|93348|假设您在Eclipse中设置了一个名为AXIS2_HOME的变量，该变量指向c:\javalibs\axis2-1.4.1，这个示例使用"for“命令迭代c：\javalibs\axis目录中的所有.jar文件，并将一个名为addto.classpath的文件写入.classpath节点。(注意:在命令行中，字符%5E对<和>进行转义，因此它们不会执行通常执行的操作。)|93349|for+%25i+in+(c:\javalibs\axis2-1.4.1\lib\*.jar)+do+@echo+++++%5E<classpathentry+kind="var"+path="AXIS2_HOME/lib/%25~ni%25~xi"/%5E>++>>+addto.classpath|code-block|syntax|javascript|93350|你最终会在文件中看到类似这样的东西...|93351|<classpathentry+kind="var"+path="AXIS2_HOME/lib/activation-1.1.jar"/>
<classpathentry+kind="var"+path="AXIS2_HOME/lib/annogen-0.1.0.jar"/>
<classpathentry+kind="var"+path="AXIS2_HOME/lib/axiom-api-1.2.7.jar"/>
<classpathentry+kind="var"+path="AXIS2_HOME/lib/axiom-dom-1.2.7.jar"/>
...|93352|因此，您可以复制这些行，并将它们粘贴到实际.classpath文件中明显的位置。|93353|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

On a windows machine you could do what uzhin said with a one liner on the command line.

Supposing you had set up a variable in Eclipse called AXIS2_HOME that points to c:\javalibs\axis2-1.4.1, this example uses the "for" command to iterate all of the .jar files in the c:\javalibs\axis\lib directory and writes the .classpath nodes a file called addto.classpath. (Note: The carat character ^ escapes the &lt; and > on the command line so they don't do what they usually do.)

<pre><code>for %i in (c:\javalibs\axis2-1.4.1\lib\*.jar) do @echo ^&lt;classpathentry kind="var" path="AXIS2_HOME/lib/%~ni%~xi"/^&gt; &gt;&gt; addto.classpath
</code></pre>

You end up with something like this in the file...

<pre><code>&lt;classpathentry kind="var" path="AXIS2_HOME/lib/activation-1.1.jar"/&gt;
&lt;classpathentry kind="var" path="AXIS2_HOME/lib/annogen-0.1.0.jar"/&gt;
&lt;classpathentry kind="var" path="AXIS2_HOME/lib/axiom-api-1.2.7.jar"/&gt;
&lt;classpathentry kind="var" path="AXIS2_HOME/lib/axiom-dom-1.2.7.jar"/&gt;
...
</code></pre>

So then you can copy those lines and paste them in the obvious place in the actual .classpath file.

blocks|key|4881871|text|我使用的是我在阅读similar+question之后开发的变通方法。我之所以把它贴在这里，是因为这个问题的范围有点不同，而且可能不清楚如何使用那里写的建议。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4881872|4881873|创建新的动态web项目(默认设置为ok，因此速度更快)|ordered-list-item|4881874|在jars所在的主项目中删除目录"lib“，但将其创建为指向主项目中jars所在目录的链接|4881875|检查项目的”排序和导出“选项卡上的”Web应用程序库“选项|4881876|将这个新创建的项目作为主项目的依赖项添加到主项目|4881877|G212|4881878|对项目中的每个lib目录执行此操作很烦人，但这总比每次更新svn时手动添加jars要好(来自使用Idea的幸运同事)。令人遗憾的是Eclipse没有这个特性。|4881879|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/1194119/jar-file-folder-for-eclipse-projects^0|9|G|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]|$1|D|3|-4|5|6|7|13|8|@]|9|@]|C|$]]|$1|E|3|F|5|G|7|14|8|@]|9|@]|C|$]]|$1|H|3|I|5|G|7|15|8|@]|9|@]|C|$]]|$1|J|3|K|5|G|7|16|8|@]|9|@]|C|$]]|$1|L|3|M|5|G|7|17|8|@]|9|@]|C|$]]|$1|N|3|O|5|6|7|18|8|@]|9|@]|C|$]]|$1|P|3|Q|5|6|7|19|8|@]|9|@]|C|$]]|$1|R|3|-4|5|6|7|1A|8|@]|9|@]|C|$]]]|S|$T|$5|U|V|W|C|$X|Y]]]]

I'm using workaround which I developed after reading <a href="https://stackoverflow.com/questions/1194119/jar-file-folder-for-eclipse-projects">similar question</a>. I'm posting it here, because that question has a little bit different scope and it might not be obvious how to use suggestions written there.

<ol>
<li>Create new dynamic web project (default settings is ok so it is fast)</li>
<li>Delete directory "lib" under WebContent/WEB-INF/</li>
<li>Recreate that directory, but create it as link to the directory in your main project where your jars are located</li>
<li>Check Web App Libraries option on Order and Export tab in Java Build Path settings of your project</li>
<li>Add this newly created project as a dependency to your main project</li>
</ol>

It's irritating to do this for every lib directory in your project but it's better than adding jars manually every time you do svn update (from your luckier colleagues using Idea). It's a shame that Eclipse don't have this feature.

blocks|key|4881959|text|您可以使用Eclipse中的用户库来组织一组jar文件。如果您有一组在多个项目中使用的jar文件，则可以创建一个用户库来引用这组jar文件。因此，您需要在项目的构建路径中包含的只是用户库，而不是所有单独的jar文件。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4881960|<classpathentry+kind="con"+path="org.eclipse.jdt.USER_LIBRARY/User+Library+name"/>|code-block|syntax|javascript|4881961|http://www.avajava.com/tutorials/lessons/what-is-a-user-library-and-how-do-i-use-it.html;jsessionid=ACD75E0A035BDC3AC656B481A7830FB6|offset|length|4881962|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|0|3O|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|T|8|@]|9|@$I|U|J|V|1|W]]|A|$]]|$1|K|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|H]]]]

You can use a User Library in Eclipse can be a useful way to organize a set of jar files. If you have a set of jar files that you use in several projects, you can create a User Library to reference the set of jar files. As a result, all you would need to include in your project's build path is the User Library rather than all the individual jar files.

<pre><code>&lt;classpathentry kind="con" path="org.eclipse.jdt.USER_LIBRARY/User Library name"/&gt;
</code></pre>

<a href="http://www.avajava.com/tutorials/lessons/what-is-a-user-library-and-how-do-i-use-it.html;jsessionid=ACD75E0A035BDC3AC656B481A7830FB6" rel="nofollow noreferrer">http://www.avajava.com/tutorials/lessons/what-is-a-user-library-and-how-do-i-use-it.html;jsessionid=ACD75E0A035BDC3AC656B481A7830FB6</a>

blocks|key|2768985|text|我构建了一个生成.classpath+(和.project)的工具，但它要求您在ant构建中指定jars列表。可以对它进行扩展，以读取jar文件列表。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2768986|http://sweetened.googlecode.com/|offset|length|2768987|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|W|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@$D|O|E|P|1|Q]]|A|$]]|$1|F|3|-4|5|6|7|R|8|@]|9|@]|A|$]]]|G|$H|$5|I|J|K|A|$L|C]]]]

I built a tool which generates the .classpath (and .project), but it requires you to specify the list of jars in your ant build. It could probably be extended to read a list of jar files.

<a href="http://sweetened.googlecode.com/" rel="nofollow">http://sweetened.googlecode.com/</a>

blocks|key|4881708|text|您是否尝试过在类路径中使用通配符？因此，您可以使用类似以下内容：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4881709|javac+MyApp.java+-cp+/some/path/to/libraries/*.jar|code-block|syntax|javascript|4881710|我已经有一段时间没有使用java了，所以我不确定上面的语法是否可行，但这是我所期望的语法。|4881711|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Have you tried using a wildcard in the classpath? So you would use something like:

<pre><code>javac MyApp.java -cp /some/path/to/libraries/*.jar
</code></pre>

I've not used java for a while so not sure if the above is possible, but it's what I would expect to be the syntax.

How do I configure my project buildpath to have a set of .jar files located in the same directory automatically included in the buildpath ?
Meaning that adding a new .jar file to this directory (and refreshing the project) updates the buildpath ?
Rem : I am not working in a Webapp but in a standalone Java app. I know that it is possible in a Dynamic Web Project to have all the .jars located in WEB-INF/lib to be included in the build path. Is it possible to do kind of the same include but in standalone app ?

I am using Eclipse 3.4

Eclipse buildpath automatically taking all JARs of a internal directory

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何配置我的项目构建路径，使位于同一目录下的一组.jar文件自动包含在构建路径中？这意味着向此目录添加新的.jar文件(并刷新项目)会更新构建路径吗？Rem :我不是在Webapp中工作，而是在一个独立的Java app中工作。我知道，在动态Web Project中，将WEB-INF/lib中的所有.jars都包含在构建路径中是可能的。有没有可能在独立的应用程序中做同样的包含？我使用的是Eclip

问Eclipse buildpath自动获取内部目录的所有JARs文件
EN

回答 10

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问Eclipse buildpath自动获取内部目录的所有JARs文件
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