使用OVER计算不同的值(按id分区)

Question

有没有可能结合OVER(PARTITION BY id)这样的窗口函数来计算不同的值？目前我的查询如下：

SELECT congestion.date, congestion.week_nb, congestion.id_congestion,
   congestion.id_element,
ROW_NUMBER() OVER(
    PARTITION BY congestion.id_element
    ORDER BY congestion.date),
COUNT(DISTINCT congestion.week_nb) OVER(
    PARTITION BY congestion.id_element
) AS week_count
FROM congestion
WHERE congestion.date >= '2014.01.01'
AND congestion.date <= '2014.12.31'
ORDER BY id_element, date

然而，当我尝试执行查询时，我得到了以下错误：

"COUNT(DISTINCT": "DISTINCT is not implemented for window functions"

Answer 1

不，正如错误消息所述，DISTINCT不是用windows函数实现的。将this link中的信息应用到您的案例中，您可以使用以下内容：

WITH uniques AS (
 SELECT congestion.id_element, COUNT(DISTINCT congestion.week_nb) AS unique_references
 FROM congestion
WHERE congestion.date >= '2014.01.01'
AND congestion.date <= '2014.12.31'
 GROUP BY congestion.id_element
)

SELECT congestion.date, congestion.week_nb, congestion.id_congestion,
   congestion.id_element,
ROW_NUMBER() OVER(
    PARTITION BY congestion.id_element
    ORDER BY congestion.date),
uniques.unique_references AS week_count
FROM congestion
JOIN uniques USING (id_element)
WHERE congestion.date >= '2014.01.01'
AND congestion.date <= '2014.12.31'
ORDER BY id_element, date

根据情况，您还可以将子查询直接放入SELECT-list中：

SELECT congestion.date, congestion.week_nb, congestion.id_congestion,
   congestion.id_element,
ROW_NUMBER() OVER(
    PARTITION BY congestion.id_element
    ORDER BY congestion.date),
(SELECT COUNT(DISTINCT dist_con.week_nb)
    FROM congestion AS dist_con
    WHERE dist_con.date >= '2014.01.01'
    AND dist_con.date <= '2014.12.31'
    AND dist_con.id_element = congestion.id_element) AS week_count
FROM congestion
WHERE congestion.date >= '2014.01.01'
AND congestion.date <= '2014.12.31'
ORDER BY id_element, date

Answer 2

我发现最简单的方法是使用子查询/CTE和条件聚合：

SELECT c.date, c.week_nb, c.id_congestion, c.id_element,
       ROW_NUMBER() OVER (PARTITION BY c.id_element ORDER BY c.date),
       (CASE WHEN seqnum = 1 THEN 1 ELSE 0 END) as week_count
FROM (SELECT c.*,
             ROW_NUMBER() OVER (PARTITION BY c.congestion.id_element, c.week_nb
                                ORDER BY c.date) as seqnum
      FROM congestion c
     ) c
WHERE c.date >= '2014.01.01' AND c.date <= '2014.12.31'
ORDER BY id_element, date

Answer 3

使分区集更小，直到没有重复的计数字段：

SELECT congestion.date, congestion.week_nb, congestion.id_congestion,
   congestion.id_element,
ROW_NUMBER() OVER(
    PARTITION BY congestion.id_element
    ORDER BY congestion.date),
COUNT(congestion.week_nb) -- remove distinct 
OVER(
    PARTITION BY congestion.id_element,
                 -- add new fields which will restart counter in case duplication
                 congestion.id_congestion
) AS week_count
FROM congestion
WHERE congestion.date >= '2014.01.01'
AND congestion.date <= '2014.12.31'
ORDER BY id_element, date