reactive-banana 1.0 monadic :现在如何定义递归行为？

Question

在reactive-banana <1.0.0中，这是可行的：

-- takes a start value, minimum and maximum value, flag whether counter is
-- cyclic, an increment and decrement event stream and returns a behavior
mkCounter :: (Enum a,Ord a) => a -> Maybe a -> Maybe a -> Bool
          -> Event t b -> Event t c -> Behavior t a
mkCounter start minVal maxVal cyclic incE decE = counter
  let incF curr | isNothing maxVal = succ
                | Just maxv <- maxVal, curr<maxv = succ
                | Just maxv <- maxVal, Just minv <- minVal, cyclic = const minv
                | otherwise = id
      decF curr | isNothing minVal = pred
                | Just minv <- minVal, curr>minv = pred
                | Just minv <- minVal, Just maxv <- maxVal, cyclic = const maxv
                | otherwise = id
  counter = accumB start $ ((incF <$> counter) <@ incE) `union`((decF <$> counter) <@ decE)

现在，counter是根据它自己来定义的。但是在新的monadic中，accumB是一个一元函数，这就是我不知道如何继续的地方-- Moment没有MonadFix实例，那么它现在是如何工作的呢？

由于明显的原因，这不起作用(‘不在作用域:计数器’)

mkCounter :: (MonadMoment m,Enum a,Ord a) => a -> Maybe a -> Maybe a -> Bool
          -> Event b -> Event c -> m (Behavior a)
mkCounter start minVal maxVal cyclic incE decE = do
  -- .. same as above ..
  counter <- accumB start $ unions [((incF <$> counter) <@ incE)
                                   ,((decF <$> counter) <@ decE)]
  return counter

现在做这件事的正确方法是什么？提前感谢！

Answer 1

好吧，这是个愚蠢的错误。我只需要添加MonadFix m作为约束，因为我没有直接使用Moment Monad：

mkCounter :: (MonadFix m,MonadMoment m,Enum a,Ord a) => a -> Maybe a -> Maybe a -> Bool
          -> Event b -> Event c -> m (Behavior a)

然后，它可以像预期的那样与mdo一起工作。