如何使用python读取7z文件的内容

Question

如何读取和保存7z的内容。我使用python 2.7.9，我可以像这样提取或归档，但我不能读取Python中的内容，我只列出CMD格式的文件内容

import subprocess
import os

source = 'filename.7z'
directory = 'C:\Directory'
pw = '123456'
subprocess.call(r'"C:\Program Files (x86)\7-Zip\7z.exe" x '+source +' -o'+directory+' -p'+pw)

Answer 1

如果你能使用Python3，有一个很有用的库，py7zr，它支持7zip压缩，解压缩，加密和解密。

import py7zr
with py7zr.SevenZipFile('sample.7z', mode='r') as z:
    z.extractall()

Answer 2

在这种情况下，我被迫使用7z，并且还需要确切地知道从每个zip归档文件中提取了哪些文件。要处理此问题，您可以检查对7z的调用的输出，并查找文件名。下面是7z的输出：

$ 7z l sample.zip

7-Zip [64] 16.02 : Copyright (c) 1999-2016 Igor Pavlov : 2016-05-21
p7zip Version 16.02 (locale=utf8,Utf16=on,HugeFiles=on,64 bits,8 CPUs x64)

Scanning the drive for archives:
1 file, 472 bytes (1 KiB)

Listing archive: sample.zip

--
Path = sample.zip
Type = zip
Physical Size = 472

   Date      Time    Attr         Size   Compressed  Name
------------------- ----- ------------ ------------  ------------------------
2018-12-01 17:09:59 .....            0            0  sample1.txt
2018-12-01 17:10:01 .....            0            0  sample2.txt
2018-12-01 17:10:03 .....            0            0  sample3.txt
------------------- ----- ------------ ------------  ------------------------
2018-12-01 17:10:03                  0            0  3 files

以及如何使用python解析该输出：

import subprocess

def find_header(split_line):
    return 'Name' in split_line and 'Date' in split_line

def all_hyphens(line):
    return set(line) == set('-')

def parse_lines(lines):
    found_header = False
    found_first_hyphens = False
    files = []
    for line in lines:

        # After the header is a row of hyphens
        # and the data ends with a row of hyphens
        if found_header:
            is_hyphen = all_hyphens(''.join(line.split()))

            if not found_first_hyphens:
                found_first_hyphens = True
                # now the data starts
                continue

            # Finding a second row of hyphens means we're done
            if found_first_hyphens and is_hyphen:
                return files

        split_line = line.split()

        # Check for the column headers
        if find_header(split_line):
            found_header=True
            continue

        if found_header and found_first_hyphens:
            files.append(split_line[-1])
            continue

    raise ValueError("We parsed this zipfile without finding a second row of hyphens")



byte_result=subprocess.check_output('7z l sample.zip', shell=True)
str_result = byte_result.decode('utf-8')
line_result = str_result.splitlines()
files = parse_lines(line_result)

Answer 3

您可以使用libarchive或pylzma。如果您可以升级到python3.3+，则可以使用标准库中的lzma。