从GetResponseStream读取HTTP响应的最佳方式是什么?
目前,我正在使用以下方法。
Using SReader As StreamReader = New StreamReader(HttpRes.GetResponseStream)
SourceCode = SReader.ReadToEnd()
End Using我不太确定这是否是读取http响应的最有效的方法。
我需要字符串形式的输出,我已经看到一个具有不同方法的article,但我不太确定它是否是一个好的方法。在我的测试中,代码在不同的网站上有一些编码问题。
你如何阅读网络回复?
发布于 2008-09-26 01:43:46
我使用类似下面的代码从URL下载文件:
if (!Directory.Exists(localFolder))
{
Directory.CreateDirectory(localFolder);
}
try
{
HttpWebRequest httpRequest = (HttpWebRequest)WebRequest.Create(Path.Combine(uri, filename));
httpRequest.Method = "GET";
// if the URI doesn't exist, an exception will be thrown here...
using (HttpWebResponse httpResponse = (HttpWebResponse)httpRequest.GetResponse())
{
using (Stream responseStream = httpResponse.GetResponseStream())
{
using (FileStream localFileStream =
new FileStream(Path.Combine(localFolder, filename), FileMode.Create))
{
var buffer = new byte[4096];
long totalBytesRead = 0;
int bytesRead;
while ((bytesRead = responseStream.Read(buffer, 0, buffer.Length)) > 0)
{
totalBytesRead += bytesRead;
localFileStream.Write(buffer, 0, bytesRead);
}
}
}
}
}
catch (Exception ex)
{
// You might want to handle some specific errors : Just pass on up for now...
// Remove this catch if you don't want to handle errors here.
throw;
}发布于 2010-06-01 01:48:33
我对字符串执行此操作的简单方法。请注意StreamReader构造函数上的true第二个参数。这告诉它从字节顺序标记中检测编码,并可能有助于解决您遇到的编码问题。
string target = string.Empty;
HttpWebRequest httpWebRequest = (HttpWebRequest)WebRequest.Create("http://www.informit.com/guides/content.aspx?g=dotnet&seqNum=583");
HttpWebResponse response = (HttpWebResponse)httpWebRequest.GetResponse();
try
{
StreamReader streamReader = new StreamReader(response.GetResponseStream(),true);
try
{
target = streamReader.ReadToEnd();
}
finally
{
streamReader.Close();
}
}
finally
{
response.Close();
}发布于 2009-05-10 21:50:50
也许您可以研究一下WebClient类。下面是一个示例:
using System.Net;
namespace WebClientExample
{
class Program
{
static void Main(string[] args)
{
var remoteUri = "http://www.contoso.com/library/homepage/images/";
var fileName = "ms-banner.gif";
WebClient myWebClient = new WebClient();
myWebClient.DownloadFile(remoteUri + fileName, fileName);
}
}
}https://stackoverflow.com/questions/137285
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