Python字符串帮助夏威夷单词发音

Question

在我为word输入值之后，我很难弄清楚为什么我的代码不能打印出任何东西。我可以输入一个单词，但是在通过while循环求值之后，它不会输出任何内容。你的想法是什么？

ai = "eye-"
ae = "eye-"
ao = "ow-"
au = "ow-"
ei = "ay-"
eu = "eh-oo-"
iu = "ew-"
oi = "oy-"
ou = "ow-"
ui = "ooey-"
a = "ah-"
e = "eh-"
i = "ee-"
o = "oh-"
u = "oo-"
p = "p"
k = "k"
h = "h"
l = "l"
m = "m" 
n = "n"

word = input("Please enter a Hawaiian word you want pronounced")
character_count1 = int(0)
character_count2 = int(1)
pronunciation = "" 
while character_count1 < len(word):
    if word[character_count1:character_count2] == ai or word[character_count1:character_count2] == "ae"or word[character_count1:character_count2] == "ao"or word[character_count1:character_count2] == "ei"or word[character_count1:character_count2] == "eu"or word[character_count1:character_count2] == "iu"or word[character_count1:character_count2] == "oi"or word[character_count1:character_count2] == "ou":
        print("your word",pronunciation + word[character_count1:character_count2])
        character_count1 + 2 and character_count2 + 2
    elif word[character_count1:character_count1] == a or word[character_count1:character_count1] == e or word[character_count1:character_count1] == i or word[character_count1:character_count1] == o or word[character_count1:character_count1] == p or word[character_count1:character_count1] == k or word[character_count1:character_count1] == h or word[character_count1:character_count1] == l or word[character_count1:character_count1] == m or word[character_count1:character_count1] == n:
        print("your word",pronunciation + word[character_count1:character_count1] )
        character_count1 + 1 and character_count2 + 1

Answer 1

如果你使用一种叫做字典的数据结构，这是python中的一种非常基本的数据结构，那么你想要实现什么是相当容易的。像这样更改数据结构：

dic={"ai" :"eye-","ae" :"eye-","ao":  "ow-","au" :"ow-"......}

现在，您可以使用键(单词)访问值(发音)。

像这样，

dic["ai"]

您将获得：

eye-

所以，现在让我们试着得到解决方案：

定义一个字典。

 dic={"ai" :"eye-","ae" :"eye-","ao":  "ow-","au" :"ow-"......}

接受输入，如果不使用python3，最好使用raw_input

word = raw_input("Please enter a Hawaiian word you want pronounced")

用空格分隔输入并形成一个列表。

lst=word.split()

使用lst的元素作为字典key来查找value。遍历列表并检查输入是否与dic的任何键匹配

for i in lst:
    print dic.get(i)

如果key不存在，将打印None。

由于我对您的要求不是很清楚，我已经包含了解决问题所需的所有内容。

因此，在需要的地方使用它们并解决问题。

祝你编码愉快。

Answer 2

答案和评论中那些说“使用字典”的人是对的，但你不能一次只循环输入一个字符，因为你有重叠的匹配。如果不看下一个字符，就无法判断"a“是"ai”还是"an“的一部分，而且这些情况的处理方式也不同。这是一个完整的带有注释的解决方案，它可以处理细微之处，并在遇到非法字符串时提供信息性的错误消息。

hawaiian_pronunciation = {
        "ai": "eye-",
        "ae": "eye-",
        "ao": "ow-",
        "au": "ow-",
        "ei": "ay-",
        "iu": "ew-",
        "oi": "oy-",
        "ui": "ooey-",
        "a": "ah-",
        "e": "eh-",
        "i": "ee-",
        "o": "oh-",
        "u": "oo-",
        "p": "p",
        "k": "k",
        "h": "h",
        "l": "l",
        "m": "m",
        "n": "n"
    }

def segment(word, start):
    # we have to consider the longest possible segment first
    # so that hai gets tokenized h-ai instead of h-a-i
    for length in (2,1):
        # check if the length of the segment puts us past the end of the word
        # the upper bound can be equal to the length of the word since the 
        # string[upper_bound] is not actually included in the range
        if start+length > len(word):
            continue 

        # the input segment we are considering
        input = word[start:start+length]
        # is it in our dictionary?
        if input in hawaiian_pronunciation:
            # if it is get the corresponding pronunciation
            output = hawaiian_pronunciation[input]
            # return the output and length for a successful match
            return output, length
    # if no candidate matches, raise an exception describing where you were
    # when you failed to find a match
    raise Exception("cannot match word {} at position {}, bad segment {}",
            word, start, word[start:])

def pronounce(word):
    "generate pronunciation from word"
    # build a list of strings
    out = []
    # we have to use a while loop and an explicit index 
    # because we can jump by one or two spaces depending on the length of the match
    start = 0
    while start < len(word):
        # when we get a match, append the new sound and
        # advance the appropriate number of spaces
        new_sound, length = segment(word, start)
        out.append(new_sound)
        start += length
    return "".join(out)

def main():
    print pronounce("hai")

main()