MagicalRecord获取两个具有row和sections的实体并对Sections进行排序

Question

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我有两个对象GroupExercise <->练习，需要做tableView的获取请求与部分(标题GroupExercise.name)和行(Exercise.name)如何才能获取两个实体与神奇的记录或核心数据

练习对象

    @interface Exercise : NSManagedObject
    @property (nonatomic, retain) NSString * name;
    @property (nonatomic, retain) NSNumber * timeRelax;
    @property (nonatomic, retain) NSNumber * type;
    @property (nonatomic, retain) NSNumber * uid;
    @property (nonatomic, retain) NSNumber * uidGroup;
    @property (nonatomic, retain) GroupExercise *groupEdge;

GroupExerciseObject

@property (nonatomic, retain) NSString * name;
@property (nonatomic, retain) NSString * tagColor;
@property (nonatomic, retain) NSNumber * uid;
@property (nonatomic, retain) NSOrderedSet *exerciseEdge;

使用代码保存对象

- (void)parseAndSaveJson:(id)json withCompleteBlock:(void (^)())completeBlock {

NSMutableArray *groupsArray = (NSMutableArray *) json;

NSLog(@"%@", json);

if (groupsArray != nil) {

    NSArray *allEntities = [NSManagedObjectModel MR_defaultManagedObjectModel].entities;

    [allEntities enumerateObjectsUsingBlock:^(NSEntityDescription *entityDescription, NSUInteger idx, BOOL *stop) {
        [NSClassFromString([entityDescription managedObjectClassName]) MR_truncateAll];
    }];

    [MagicalRecord saveWithBlock:^(NSManagedObjectContext *localContext) {


        for (int groupIndex = 0; groupIndex < [groupsArray count]; groupIndex++) {


            GroupExercise *localGroup = [GroupExercise MR_createEntityInContext:localContext];

            localGroup.name = groupsArray[groupIndex][LOCAL_GROUPS_NAME];

            localGroup.tagColor = groupsArray[groupIndex][LOCAL_GROUPS_TAG_COLOR];

            localGroup.uid = @([groupsArray[groupIndex][LOCAL_GROUPS_ID_GROUP] intValue]);


            NSMutableArray *exerciseArray = (NSMutableArray *) groupsArray[groupIndex][LOCAL_GROUPS_EXERCISES];

            NSMutableSet *set = [[NSMutableSet alloc] init];

            for (int exerciseIndex = 0; exerciseIndex < [exerciseArray count]; exerciseIndex++) {

                Exercise *exercise = [Exercise MR_createEntityInContext:localContext];

                exercise.name = exerciseArray[exerciseIndex][EXERCISE_NAME];
                exercise.uid = @([exerciseArray[exerciseIndex][LOCAL_EXERCISE_ID_EXERCISE] intValue]);
                exercise.uidGroup = @([groupsArray[groupIndex][LOCAL_GROUPS_ID_GROUP] intValue]);
                exercise.groupEdge = localGroup;

                [set addObject:exercise];
            }

            [localGroup addExerciseEdge:set];
        }

    }                 completion:^(BOOL contextDidSave, NSError *error) {

        completeBlock();

    }];
}
}

并使用FRC

- (NSFetchedResultsController *)fetchedResultsController {
if (_fetchedResultsController != nil) {
    return _fetchedResultsController;
}

_fetchedResultsController = [Exercise MR_fetchAllGroupedBy:@"groupEdge" withPredicate:nil sortedBy:@"uid" ascending:true];


_fetchedResultsController.delegate = self;
return _fetchedResultsController;
}

如何使用groupEdge.name对节进行排序？

Answer 1

我用代码解决了问题

_fetchedResultsController = [Exercise MR_fetchAllGroupedBy:@"groupEdge" withPredicate:nil sortedBy:@"uidGroup,uid" ascending:true];