Python API调用multipart/form-data

Question

我正在尝试使用Python的--form data来转换curl调用

curl -H "X-API-TOKEN:xxxxxxxxxxxxxxxxxxxxxxxxxx" -X POST \
    --form upload=@2015-07-02-Fiesta-EK-malware-payload.exe \
    --form "owner=userName" https://192.168.1.198/rapi/samples/basic

我尝试过的：

url = 'https://%s/rapi/samples/basic' % hostname
q = Request(url)
q.add_header('X-API-TOKEN', 'xxxxxxxxxxxxxxxxxxxxxxxxxx')
q.add_header('Content-Type', 'multipart/form-data; upload=@%s' % fileName)
q.add_header('Content-Type', 'multipart/form-data; owner=userName')
a = urlopen(q).read()

我得到的返回值是所有已提交样本的默认列表。所以我确信它不会得到所有的头数据。

我可以使用一个传递多个表单数据头的示例。

谢谢。

Answer 1

使用unirest的示例调用

import unirest

# consume async post request
def consumePOSTRequestSync():
 params = {'test1':'param1','test2':'param2'}

 # we need to pass a dummy variable which is open method
 # actually unirest does not provide variable to shift between
 # application-x-www-form-urlencoded and
 # multipart/form-data
 params['dummy'] = open('dummy.txt', 'r')
 url = 'http://httpbin.org/post'
 headers = {"Accept": "application/json"}
 # call get service with headers and params
 response = unirest.post(url, headers = headers,params = params)
 print "code:"+ str(response.code)
 print "******************"
 print "headers:"+ str(response.headers)
 print "******************"
 print "body:"+ str(response.body)
 print "******************"
 print "raw_body:"+ str(response.raw_body)

# post sync request multipart/form-data
consumePOSTRequestSync()

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