我得到了这个错误:
Cannot invoke initialiser for type 'JSON' with an argument list of type (data: NSUrlConnection?)当我尝试执行这段代码时:
var url = NSURL(string: "http://****")
var request = NSMutableURLRequest(URL: url!, cachePolicy: NSURLRequestCachePolicy.ReturnCacheDataElseLoad, timeoutInterval: Double.infinity);
if IJReachability.isConnectedToNetwork(){
request = NSMutableURLRequest(URL: url!, cachePolicy: NSURLRequestCachePolicy.UseProtocolCachePolicy, timeoutInterval: Double.infinity);
}
var response: NSURLResponse?
let data = NSURLConnection?
do {
data = try NSURLConnection.sendSynchronousRequest(request, returningResponse: &response)
} catch (let e) {
print(e)
}
if data != nil {
var dataArray = JSON(data: data)
let dutch_sentence = dataArray[id]["dutch_sentence"]
let polish_sentence = dataArray[id]["polish_sentence"]
let navigationTitle = dutch_sentence.string!.uppercaseString
self.title = navigationTitle
//Populate labels
dutchSentenceLabel.text = dutch_sentence.string!
polishSentenceLabel.text = polish_sentence.string!
}我是Swift的新手,我正在尝试修复我的代码中的错误,因为它已经更新了,但我在这方面遇到了困难,因为我没有使用该语言的经验。有谁能帮帮我吗?如果我已经把整个代码搞乱了,我也不会感到惊讶..
我还尝试了这个:
let url = NSURL(string: "http://****")
var request = NSMutableURLRequest(URL: url!, cachePolicy: NSURLRequestCachePolicy.ReturnCacheDataElseLoad, timeoutInterval: Double.infinity);
if IJReachability.isConnectedToNetwork(){
request = NSMutableURLRequest(URL: url!, cachePolicy: NSURLRequestCachePolicy.UseProtocolCachePolicy, timeoutInterval: Double.infinity);
}
let task = NSURLSession.sharedSession().dataTaskWithRequest(request) { (data, response, error) -> Void in
var dataArray = JSON(data: data!)
let dutch_sentence = dataArray[self.id]["dutch_sentence"]
let polish_sentence = dataArray[self.id]["polish_sentence"]
let navigationTitle = dutch_sentence.string!.uppercaseString
self.title = navigationTitle
//Populate labels
self.dutchSentenceLabel.text = dutch_sentence.string!
self.polishSentenceLabel.text = polish_sentence.string!
}
task.resume()它没有错误,但我不知道它是否是正确的方式,以及它是否可以工作。我必须在很多地方替换它,所以在我这样做之前,我想确定它是否有效。
发布于 2015-09-23 04:19:47
我相信你打算用JSONObjectWithData:options:error
除非您是使用SwiftyJSON执行此操作。如果是这样的话,这里有一个详细介绍如何安装和使用它的excellent article。
https://stackoverflow.com/questions/32725952
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