我正在寻找一个在保存CKRecord时正确处理错误的示例。根据Apple docs的说法,我应该“使用error对象中的信息来确定问题是否有解决方法”。
我知道error对象有一个userInfo字典,但是我如何确定字典的键是什么以及如何处理错误呢?
下面的示例说明了我当前如何保存CKRecord
CKRecord *record = [[CKRecord alloc] initWithRecordType:@"MyRecordType"];
[record setValue:[NSNumber numberWithInt:99] forKey:@"myInt"];
[db saveRecord:record completionHandler:^(CKRecord *savedPlace, NSError *error) {
// handle errors here
if (savedPlace) {
NSLog(@"save successful");
}else{
NSLog(@"save unsuccessful");
}
if (error) {
NSLog(@"Error saving %@", error.localizedDescription);
}
}];我如何改进这段代码,以便为潜在的保存问题提供解决方案?
发布于 2015-09-17 15:53:32
在我的库EVCloudKitDao中,我有一个单独的方法,它将根据错误代码返回错误类型。根据类型的不同,您可以决定要做什么。以下是该方法:
public enum HandleCloudKitErrorAs {
case Success,
Retry(afterSeconds:Double),
RecoverableError,
Fail
}
public static func handleCloudKitErrorAs(error:NSError?, retryAttempt:Double = 1) -> HandleCloudKitErrorAs {
if error == nil {
return .Success
}
let errorCode:CKErrorCode = CKErrorCode(rawValue: error!.code)!
switch errorCode {
case .NetworkUnavailable, .NetworkFailure, .ServiceUnavailable, .RequestRateLimited, .ZoneBusy, .ResultsTruncated:
// Use an exponential retry delay which maxes out at half an hour.
var seconds = Double(pow(2, Double(retryAttempt)))
if seconds > 1800 {
seconds = 1800
}
// Or if there is a retry delay specified in the error, then use that.
if let userInfo = error?.userInfo {
if let retry = userInfo[CKErrorRetryAfterKey] as? NSNumber {
seconds = Double(retry)
}
}
NSLog("Debug: Should retry in \(seconds) seconds. \(error)")
return .Retry(afterSeconds: seconds)
case .UnknownItem, .InvalidArguments, .IncompatibleVersion, .BadContainer, .MissingEntitlement, .PermissionFailure, .BadDatabase, .AssetFileNotFound, .OperationCancelled, .NotAuthenticated, .AssetFileModified, .BatchRequestFailed, .ZoneNotFound, .UserDeletedZone, .InternalError, .ServerRejectedRequest, .ConstraintViolation:
NSLog("Error: \(error)")
return .Fail;
case .QuotaExceeded, .LimitExceeded:
NSLog("Warning: \(error)")
return .Fail;
case .ChangeTokenExpired, .ServerRecordChanged:
NSLog("Info: \(error)")
return .RecoverableError
default:
NSLog("Error: \(error)") //New error introduced in iOS...?
return .Fail;
}
}在CloudKit方法的回调中,您可以像这样使用此函数:
func loadContacts(retryCount:Double = 1) {
// Look who of our contact is also using this app.
EVCloudKitDao.publicDB.allContactsUserInfo({ users in
EVLog("AllContactUserInfo count = \(users.count)");
Async.main{
self.contacts = users
self.tableView.reloadData()
}
}, errorHandler: { error in
switch EVCloudKitDao.handleCloudKitErrorAs(error, retryAttempt: retryCount) {
case .Retry(let timeToWait):
Async.background(after: timeToWait) {
self.loadContacts(retryCount + 1)
}
case .Fail:
Helper.showError("Something went wrong: \(error.localizedDescription)")
default: // For here there is no need to handle the .Success, .Fail and .RecoverableError
break
}
})
}在上面的例子中,我使用了一个单独的错误回调处理程序。您也可以在CloudKit方法回调中直接调用它。只需首先检查是否有错误。
发布于 2015-09-17 11:00:50
下面是一个实现,在这个实现中,我通过在存储在userInfo字典中的建议重试时间间隔后重试保存来处理CKErrorNetworkFailure的常见错误。
-(void)saveRecord:(CKRecord*)record toDatabase:(CKDatabase*)database{
[database saveRecord:record completionHandler:^(CKRecord *record, NSError *error) {
if (error==nil) {
NSLog(@"The save was successful");
//Do something
}else{
NSLog(@"Error saving with localizedDescription: %@", error.localizedDescription);
NSLog(@"CKErrorCode = %lu", [error code]);
if ([error code]==CKErrorNetworkFailure) {
double retryAfterValue = [[error.userInfo valueForKey:CKErrorRetryAfterKey] doubleValue];
NSLog(@"Error code network unavailable retrying after %f", retryAfterValue);
NSTimer *timer = [NSTimer timerWithTimeInterval:retryAfterValue target:self selector:@selector(testOutCloudKit) userInfo:nil repeats:NO];
[timer fire];
}
}
}];}
发布于 2016-10-13 04:53:08
在Swift 3中,我这样处理我的CloudKit错误:
privateDB.perform(myQuery, inZoneWith: nil) {records, error in
if error != nil {
print (error?.localizedDescription)
if error?._code == CKError.notAuthenticated.rawValue {
// Solve problems here...
}请注意,在编写CKError之后,将从代码完成显示的列表中选择CKError.notAuthenticated。
希望这能有所帮助!
https://stackoverflow.com/questions/32621306
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