我正在尝试解析node中的xmi:type。但不能成功做到这一点。我附上了输入文件(uml - xmi格式),我的xslt输入和我得到的输出(xml格式)。每当我看到"xmi:type = uml:OpaqueAction“时,我想修改输出来写一行。我可以访问同一行中的"name“,但不能访问xmi:type。不知道为什么
UML-XMI输入
<?xml version="1.0" encoding="UTF-8"?>
<uml:Model xmi:version="20110701" xmlns:xmi="http://www.omg.org/spec/XMI/20110701" xmlns:uml="http://www.eclipse.org/uml2/4.0.0/UML" xmi:id="_OlYJkC9-EeWyX7UKkcyxiw" name="model">
<packagedElement xmi:type="uml:Activity" xmi:id="_OlYJkS9-EeWyX7UKkcyxiw" name="Activity1" node="_XjLyEC9-EeWyX7UKkcyxiw _ZfIhYC9-EeWyX7UKkcyxiw _cK4V8C9-EeWyX7UKkcyxiw _fE2zwC9-EeWyX7UKkcyxiw _F67sgC9_EeWyX7UKkcyxiw">
<edge xmi:type="uml:ControlFlow" xmi:id="_jzMLIC9-EeWyX7UKkcyxiw" name="ControlFlow" source="_XjLyEC9-EeWyX7UKkcyxiw" target="_ZfIhYC9-EeWyX7UKkcyxiw"/>
<edge xmi:type="uml:ControlFlow" xmi:id="_lieXcC9-EeWyX7UKkcyxiw" name="ControlFlow1" source="_ZfIhYC9-EeWyX7UKkcyxiw" target="_cK4V8C9-EeWyX7UKkcyxiw"/>
<edge xmi:type="uml:ControlFlow" xmi:id="_m0Vn8C9-EeWyX7UKkcyxiw" name="Timer expired" source="_cK4V8C9-EeWyX7UKkcyxiw" target="_fE2zwC9-EeWyX7UKkcyxiw"/>
<edge xmi:type="uml:ControlFlow" xmi:id="_wrhvgC9-EeWyX7UKkcyxiw" name="Timer not expired" source="_cK4V8C9-EeWyX7UKkcyxiw" target="_cK4V8C9-EeWyX7UKkcyxiw"/>
<edge xmi:type="uml:ControlFlow" xmi:id="_Hcj3UC9_EeWyX7UKkcyxiw" name="ControlFlow2" source="_fE2zwC9-EeWyX7UKkcyxiw" target="_F67sgC9_EeWyX7UKkcyxiw"/>
<node xmi:type="uml:InitialNode" xmi:id="_XjLyEC9-EeWyX7UKkcyxiw" name="Start" outgoing="_jzMLIC9-EeWyX7UKkcyxiw"/>
<node xmi:type="uml:OpaqueAction" xmi:id="_ZfIhYC9-EeWyX7UKkcyxiw" name="Load and Enable Timer" visibility="package" outgoing="_lieXcC9-EeWyX7UKkcyxiw" incoming="_jzMLIC9-EeWyX7UKkcyxiw"/>
<node xmi:type="uml:DecisionNode" xmi:id="_cK4V8C9-EeWyX7UKkcyxiw" name="Has timer expired?" outgoing="_m0Vn8C9-EeWyX7UKkcyxiw _wrhvgC9-EeWyX7UKkcyxiw" incoming="_lieXcC9-EeWyX7UKkcyxiw _wrhvgC9-EeWyX7UKkcyxiw"/>
<node xmi:type="uml:OpaqueAction" xmi:id="_fE2zwC9-EeWyX7UKkcyxiw" name="Service the Timer ISR" outgoing="_Hcj3UC9_EeWyX7UKkcyxiw" incoming="_m0Vn8C9-EeWyX7UKkcyxiw">
<inputValue xmi:type="uml:ActionInputPin" xmi:id="_82lIMDRBEeWdiarL2UAMaQ" name="interrupt">
<upperBound xmi:type="uml:LiteralInteger" xmi:id="_82lIMTRBEeWdiarL2UAMaQ" value="1"/>
</inputValue>
</node>
<node xmi:type="uml:ActivityFinalNode" xmi:id="_F67sgC9_EeWyX7UKkcyxiw" name="ActivityFinalNode" incoming="_Hcj3UC9_EeWyX7UKkcyxiw"/>
</packagedElement>
</uml:Model>XSLT输入
<xsl:stylesheet version="1.0" xmlns:UML="http://www.eclipse.org/uml2/4.0.0/UML" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns='uri:sadf' exclude-result-prefixes="UML">
<xsl:output method="xml" omit-xml-declaration="yes" encoding="UTF-8" indent="yes" />
<xsl:template match="/UML:Model">
<?xml version="1.0"?>
<sdf3 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="1.0" type="fsmsadf" xsi:noNamespaceSchemaLocation="http://www.es.ele.tue.nl/sdf3/xsd/sdf3-fsmsadf.xsd">
<applicationGraph name="g">
<xsl:apply-templates />
</applicationGraph>
</sdf3>
</xsl:template>
<xsl:template match="packagedElement">
<fsmsadf>
<scenariograph name="sg0" type="t">
<xsl:apply-templates select="node" />
</scenariograph>
</fsmsadf>
</xsl:template>
<xsl:template match="node">
<xsl:if test="@'xmi:type'='uml:OpaqueAction'">
<actor name="{@name}" source="{@outgoing}" />
</xsl:if>
</xsl:template>
</xsl:stylesheet>输出(.XML)
<?xml version="1.0" encoding="UTF-8"?>
<sdf3 xmlns="uri:sadf" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="http://www.es.ele.tue.nl/sdf3/xsd/sdf3-fsmsadf.xsd" type="fsmsadf" version="1.0">
<applicationGraph name="g">
<fsmsadf>
<scenariograph type="t" name="sg0" />
#Need these lines <actor name="Load and Enable Timer" source="whatever_input is here">
#Need these lines <actor name="Service the timer ISR" source="whatever_input is here">
</fsmsadf>
</applicationGraph>
</sdf3>发布于 2015-08-28 15:48:51
这一行有一个问题:
<xsl:if test="@'xmi:type'='uml:OpaqueAction'">正确的语法应该是:
<xsl:if test="@xmi:type='uml:OpaqueAction'">您不需要在属性名称周围使用撇号。您只需要将它们包含在字符串周围即可。您还需要在XSLT中声明xmi名称空间,名称空间URI与XML中的名称空间URI相匹配。如果您已经尝试运行XSLT,这应该会在错误消息中突出显示。
实际上,在此之前会出现另一个错误,因为这些行是无效的
<xsl:template match="/UML:Model">
<?xml version="1.0"?>也许这只是您的问题的一个拼写错误,应该在XSLT的开头出现,但是如果您实际上试图在输出XML中包含xml声明,那么只需在xsl:output元素中将omit-xml-declaration更改为"no“即可。
试试这个XSLT
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns='uri:sadf'
xmlns:UML="http://www.eclipse.org/uml2/4.0.0/UML"
xmlns:xmi="http://www.omg.org/spec/XMI/20110701"
exclude-result-prefixes="UML xmi">
<xsl:output method="xml" omit-xml-declaration="no" encoding="UTF-8" indent="yes" />
<xsl:template match="/UML:Model">
<sdf3 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="1.0" type="fsmsadf" xsi:noNamespaceSchemaLocation="http://www.es.ele.tue.nl/sdf3/xsd/sdf3-fsmsadf.xsd">
<applicationGraph name="g">
<xsl:apply-templates />
</applicationGraph>
</sdf3>
</xsl:template>
<xsl:template match="packagedElement">
<fsmsadf>
<scenariograph name="sg0" type="t">
<xsl:apply-templates select="node" />
</scenariograph>
</fsmsadf>
</xsl:template>
<xsl:template match="node">
<xsl:if test="@xmi:type='uml:OpaqueAction'">
<actor name="{@name}" source="{@outgoing}" />
</xsl:if>
</xsl:template>
</xsl:stylesheet>https://stackoverflow.com/questions/32265326
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