pythonQt捕获非整数输入

Question

当用户输入字母而不是数字时，我们只是在捕获实例时遇到问题。Get错误‘无法将编号分配给函数调用’

这是一个简单的两个QLine编辑框，其中用户必须猜测number...any帮助将不胜感激。我刚刚发布了函数位

 def my_response():
        global counter, random_number
        timer=QtCore.QTimer

        try:
            reply.text()= int(reply.text())

            if int(reply.text()) <self. random_number:
                question.setText("Your guess is too low. Please Try Again")
                reply.setText(" ")


            elif int(reply.text()) >self. random_number:
                question.setText("Your guess is too high. Please Try Again")
                reply.setText(" ")


            elif int(reply.text()) ==self. random_number:
                question.setStyleSheet('QLineEdit{color: blue}')
                question.setFont(QtGui.QFont("Stencil", 15, QtGui.QFont.Bold))
                question.setText("Correct")
                timer.singleShot(250,lambda:question.setText('You won'))
                reply.setText(" ")

        except:
            reply.setText('invalad input number is needed')

Answer 1

错误在

reply.text()= int(reply.text())

这条信息很简单--你不能给函数调用分配编号。(实际上，您不能将任何内容分配给函数调用。)

还要注意的是，您可以将inputMask或validator赋值给您的QLineEdit，并且根本不需要检查无效输入。