玩起来又有麻烦了

Question

所以这是我的代码...我想找到一种方法来再次玩...使用while循环或其他方法...有人能帮我吗？

public static void main(String[] args) {
Scanner input = new Scanner(System.in);
    System.out.print("enter minimum of Yahtzee dice 2-9: ");
    int min = input.nextInt();
    System.out.print("enter maximum of Yahtzee dice 3-10: ");
    int max = input.nextInt();
    System.out.println("Dice   Rolls\tYahtzee's Percentage  Odds\t");
    for (int i = min; i <= max; i++) {
        int count = 0;
        for (int j = 0; j <= 5000000; j++) {
            Random generator = new Random();
            YahtzeeDice d = new YahtzeeDice(generator, i);
            if (d.IsAYahtzee()) {
                count++;
            }
        }
        System.out.printf("%d     ", i);
        System.out.printf("%d\t", 5000000);
        System.out.printf("%d\t  ", count);
        System.out.printf("%f   ", (double) count / 5000000);
        double per = count / (double) 5000000;
        int odds = (int) (1 / per);
        System.out.printf("1 in %d\n", odds);
    }
}

Answer 1

你可以在你的代码中添加一个环绕的循环代码，在这里你会问“再玩一次”。如下所示：

do{

   //your code

   System.out.print("Gib was ein: ");
   String answer = br.readLine();
}while(answer.equal("yes"))

你也可以把你的代码放在一个函数中。

do{

   mcFunction

   System.out.print("Gib was ein: ");
   String answer = br.readLine();
}while(answer.equal("yes"))

public void myFunction(){
   //your code
}