首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >我可以以编程方式重命名可移动SD卡上的文件吗

我可以以编程方式重命名可移动SD卡上的文件吗
EN

Stack Overflow用户
提问于 2015-08-03 00:10:05
回答 2查看 1.6K关注 0票数 1

我尝试了下面的代码来重命名file.It在内存中工作良好,但不适用于可移动SD卡文件。我需要重命名可移动SD卡上的文件,以删除文件名中的空格和特殊字符,因为我正在使用fmpeg命令来剪切视频。

代码语言:javascript
复制
File from = new File(originalpath);
String rename=originalpath.replace(" ", "").replace("-","").replace(",","").trim();
File to = new File(rename);
Boolean result= from.renameTo(to);

代码语言:javascript
复制
File from = new File(originalpath);
File to=new File((Environment.getExternalStorageDirectory()),"gvideo.mp4");
Boolean result2= from.renameTo(to);

它们都给出了错误的结果

添加有关命令的详细信息-

代码语言:javascript
复制
execFFmpegBinary("-i " + from.getAbsolutePath() + " -ss " + startMs / 1000 + " -to " + endMs / 1000 + " -strict -2 -async 1 " + dest.getAbsolutePath());
private void execFFmpegBinary(final String command) {
        try {
            ffmpeg.execute(command, new ExecuteBinaryResponseHandler() {
                @Override
                public void onFailure(String s) {
                    Log.e("Previewragment", "FAILED with output : " + s);
                }

                @Override
                public void onSuccess(String s) {
                    Log.e("Previewragment", "SUCCESS with output : " + s);
                }

                @Override
                public void onProgress(String s) {
                    Log.e("Previewragment", "Started command : ffmpeg " + command);
                    Log.e("Previewragment", "progress : " + s);
                }

                @Override
                public void onStart() {
                    Log.e("Previewragment", "Started command : ffmpeg " + command);

                }

                @Override
                public void onFinish() {
                    Log.e("Previewragment", "Finished command : ffmpeg " + command);



                }
            });
        } catch (FFmpegCommandAlreadyRunningException e) {
            // do nothing for now
        }
    }

失败消息-

代码语言:javascript
复制
FAILED with output : WARNING: linker: /data/data/xyz/files/ffmpeg has text relocations. This is wasting memory and prevents security hardening. Please fix.
    ffmpeg version n2.4.2 Copyright (c) 2000-2014 the FFmpeg developers
    built on Oct  7 2014 15:11:41 with gcc 4.8 (GCC)
    configuration: --target-os=linux --cross-prefix=/home/sb/Source-Code/ffmpeg-android/toolchain-android/bin/i686-linux-android- --arch=x86 --cpu=i686 --enable-runtime-cpudetect --sysroot=/home/sb/Source-Code/ffmpeg-android/toolchain-android/sysroot --enable-pic --enable-libx264 --enable-libass --enable-libfreetype --enable-libfribidi --enable-fontconfig --enable-pthreads --disable-debug --disable-ffserver --enable-version3 --enable-hardcoded-tables --disable-ffplay --disable-ffprobe --enable-gpl --enable-yasm --disable-doc --disable-shared --enable-static --pkg-config=/home/sb/Source-Code/ffmpeg-android/ffmpeg-pkg-config --prefix=/home/sb/Source-Code/ffmpeg-android/build/x86 --extra-cflags='-I/home/sb/Source-Code/ffmpeg-android/toolchain-android/include -U_FORTIFY_SOURCE -D_FORTIFY_SOURCE=2 -fno-strict-overflow -fstack-protector-all -march=i686' --extra-ldflags='-L/home/sb/Source-Code/ffmpeg-android/toolchain-android/lib -Wl,-z,relro -Wl,-z,now -pie' --extra-libs='-lpng -lexpat -lm' --extra-cxxflags=
    libavutil      54.  7.100 / 54.  7.100
    libavcodec     56.  1.100 / 56.  1.100
    libavformat    56.  4.101 / 56.  4.101
    libavdevice    56.  0.100 / 56.  0.100
    libavfilter     5.  1.100 /  5.  1.100
    libswscale      3.  0.100 /  3.  0.100
    libswresample   1.  1.100 /  1.  1.100
    libpostproc    53.  0.100 / 53.  0.100
    "/storage/emulated/0/Movies/m_ASUS_Display_Demo.mp4": No such file or directory

添加了完整方法-

代码语言:javascript
复制
private void executeTrimCommand(int startMs, int endMs) {

        File moviesDir = Environment.getExternalStoragePublicDirectory(
                Environment.DIRECTORY_MOVIES
        );

        String filePrefix = "guggu";
        String fileExtn = ".mp4";
        String fileName = filePrefix + fileExtn;

       File from = new File(path);

        try {


            dest = new File(moviesDir, filePrefix + "_1" + fileExtn);

            if (dest.exists()) {
                dest.delete();
            }



            String command = String.format("-i \"%s\" -ss %d -to %d -strict -2 -async 1 \"%s\" ",path,startMs / 1000 , endMs / 1000, dest.getAbsolutePath());
            execFFmpegBinary(command);
        } catch (Exception e) {
            Log.e("Previewragment", e.toString());
            e.printStackTrace();
        }
    }
EN

回答 2

Stack Overflow用户

发布于 2015-08-03 00:44:15

对于问题中的注释,请使用字符串格式化程序:

代码语言:javascript
复制
String command = String.format("-i \"%s\" -ss %d -to %d -strict -2 -async 1 \"%s\" ",to.getAbsolutePath(),startMs / 1000 , endMs / 1000, dest.getAbsolutePath());
票数 1
EN

Stack Overflow用户

发布于 2015-08-03 01:57:51

您的问题是,在shell的上下文中,从Environment.getExternalStorageDirectory()返回的路径将抛出文件或目录不存在的错误。

您需要更改您发送的所有文件路径才能在shell中运行。下面是一个静态工厂方法,您可以使用它来获取正确的文件:

代码语言:javascript
复制
/**
 * The external storage path is not readable by shell or root. This replaces {@link
 * Environment#getExternalStorageDirectory()} with the environmental variable
 * "EXTERNAL_STORAGE"
 *
 * @param file
 *         The file to check.
 * @return The original file (if it does not start with {@link
 * Environment#getExternalStorageDirectory()})
 * or a file with the correct path.
 */
@SuppressLint("SdCardPath")
public static File fileForShell(File file) {
    String externalStorage = Environment.getExternalStorageDirectory().getAbsolutePath();
    if (!file.getAbsolutePath().startsWith(externalStorage)) {
        return file;
    }

    String legacyStorage = System.getenv("EXTERNAL_STORAGE");
    String path;

    if (legacyStorage != null) {
        path = file.getAbsolutePath().replaceFirst(externalStorage, legacyStorage);
    } else {
        path = file.getAbsolutePath().replaceFirst(externalStorage, "/sdcard");
    }

    return new File(path);
}

创建命令时,只需使用上述方法获取正确的文件路径即可。

代码语言:javascript
复制
File from = ...
File fileToUseInCommand = fileForShell(from);
...
票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/31773819

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档