当你在php中创建一个mysqli对象时,你需要给它提供数据以便它可以连接。举个例子:
$mysqli = new mysqli($address, $user, $pass, $database);有没有可能从结果对象中获取返回给它的数据?
发布于 2015-01-30 00:33:26
编号:
数据在用于开始连接后根本不存在。下面是print_r的输出
mysqli Object
(
[affected_rows] => 0
[client_info] => mysqlnd 5.0.11-dev - 20120503 - $Id: [not sure if this was sensitive information, so redacted. was just a long string of numbers] $
[client_version] => 50011
[connect_errno] => 0
[connect_error] =>
[errno] => 0
[error] =>
[error_list] => Array
(
)
[field_count] => 0
[host_info] => localhost via TCP/IP
[info] =>
[insert_id] => 0
[server_info] => 5.5.36
[server_version] => 50536
[stat] => Uptime: 294546 Threads: 1 Questions: 351 Slow queries: 0 Opens: 53 Flush tables: 1 Open tables: 0 Queries per second avg: 0.001
[sqlstate] => 00000
[protocol_version] => 10
[thread_id] => 99
[warning_count] => 0
)https://stackoverflow.com/questions/28188307
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