我正在做书中的练习,首先是android开发,并按照书中的说明进行了练习,但是输入R.id.chooser会显示chooser symbol不能解析,即使我在string XML中声明了它。这太奇怪了。有谁有解决这个问题的建议吗?
java文件:
package com.hfad.messenger;
import android.app.Activity;
import android.os.Bundle;
import android.view.View;`enter code here`
import android.content.Intent;
import android.widget.EditText;
public class CreateMessageActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_create_message);
}
//Call onSendMessage() when the button is clicked
public void onSendMessage(View view) {
EditText messageView = (EditText)findViewById(R.id.message);
String messageText = messageView.getText().toString();
Intent intent = new Intent(Intent.ACTION_SEND);
intent.setType("text/pain");
intent.putExtra(Intent.EXTRA_TEXT, messageText);
String chooserTitle = getString(R.string.chooser);
Intent chosenIntent = Intent.createChooser(intent, chooserTitle);
startActivity(chosenIntent);
}
}xml文件:
<resources>
<string name="app_name">Messenger</string>
<string name="send">Send Message</string>
<String name="chooser">Send Message...</String>
<string name="action_settings">Settings</string>
<string name="title_activity_receive_message">ReceiveMessageActivity</string>
</resources>发布于 2015-06-28 13:13:01
您已经使用大写首字母声明了chooser,例如String,但它看起来应该类似于string
<resources>
<string name="app_name">Messenger</string>
<string name="send">Send Message</string>
<string name="chooser">Send Message...</string>
<string name="action_settings">Settings</string>
<string name="title_activity_receive_message">ReceiveMessageActivity</string>
</resources>这就是Android Studio找不到chooser字符串的原因。
https://stackoverflow.com/questions/31096326
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